The answer for this will be letter d. C = 22π and A = 121π. This is computed using the formula of C= Dπ which is C = (22)π. On the other hand, the area of this circle is computed by using the formula A = <span>πr^2. This is computed as follows:
A = </span><span>πr^2
A = </span><span>π (22/2)^2
A = </span><span>π (11)^2
</span>A = 121<span>π</span><span>
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<h2><u>
Answer:</u></h2><h2><u>
</u>
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</u></h2><h2><u>
</u></h2><h2><u>
Solution Steps:</u></h2>
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<h3>1.) Combine x and 3x:</h3>
<em> - We combine the </em><em> variables because to get to the end sum of the equation, there can only be 1 variable. So to get the 1, you combine like terms. </em>
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<h3>2.) Add 19 to both sides:</h3>
- Cancels Out
- <em></em><em></em>
<em> - We do this to get 1 number left over. To do this you do the opposite of what you see. In this case we have a negative 19, so you add 19 on each side of the equals. </em>
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<h3>3.) Divide both sides by 4:</h3>
- ÷
- ÷
<em> - We do this to get x alone. To do this you do the opposite of what you see. In this case we have </em><em> which is multiplying, so you divide by 4 on each side. </em>
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So your answer is .
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Answer:
do you have a picture of the problem as well?
Step-by-step explanation:
In general 2^n is the number of pieces of information n bits can store.
(a) Antonio can use the formula 2^n-1 to indicate the maximum size of numbers an n-bit word can store.
(b) for a 16-bit system, the maximum number of keys Millie can collect is 2^(16)-1 = 65536-1=65535
(c) For a 14 byte program, there are 14*8=112 bits.
Answer:
Sn
<em>Your</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>Option</em><em> </em><em>A</em><em> </em><em>.</em>