Answer:
The probability that <em>X</em> is less than 42 is 0.1271.
Step-by-step explanation:
The random variable <em>X </em>follows a Normal distribution.
The mean and standard deviation are:
E (X) = <em>μ</em> = 50.
SD (X) = <em>σ</em> = 7.
A normal distribution is continuous probability distribution.
The Normal probability distribution with mean µ and standard deviation σ is given by,
To compute the probability of a Normal random variable we first standardize the raw score.
The raw scores are standardized using the formula:
These standardized scores are known as <em>z</em>-scores and they follow normal distribution with mean 0 and standard deviation 1.
Compute the probability of (X < 42) as follows:
*Use a <em>z</em>-table for the probability.
Thus, the probability that <em>X</em> is less than 42 is 0.1271.
The normal curve is shown below.
Correct Answer:Option A. 0.01
Solution:This is a problem of statistics and uses the concept of normal distributions. We need to convert the score of 90 into z-score and then find the desired probability from standard normal distribution table.
Converting 90 to z-score:
Now we are to find the probability of z score being more than 2.33. From the z-table the probability comes out to be 0.01.
Therefore, we can conclude that the probability of class average is greater than 90 is 0.01.
Answer:
1-6 you need to write the JHI DEF where the radius center point is in the middle of each shape next to 1-6 some have 2 shapes so use 6 letters there.
Step-by-step explanation:
1. Area = 72 of 360 = 20% of 716.3 = 143.26inch*2 =JHI
2.Area = 19 of 360 = 68.4% of 69.4 = 47.46km^2 =DEF
3. Area = 92 of 360 = 25.56% of 153.9 = 39.33cm^2
4. Area = 226 of 360 = 64.57% of 706.9 = 456.45ft^2
5. Area = 74 of 360 = 20.55% of 153.9 =31.63 inch^2
6. Area = 326 of 360 = 90.56% of 1452 -137.07 = 1314.93m^2
Step-by-step explanation:
Below are the null and alternative Hypothesis,
Null Hypothesis, H0: μ = 35000
Alternative Hypothesis, Ha: μ < 35000
Test statistic,
z = (xbar - mu)/(sigma/sqrt(n))
z = (33450 - 35000)/(5978/sqrt(50))
z = -1.83
P-value Approach
P-value = 0.0336
As P-value >= 0.02, fail to reject null hypothesis.
There is not sufficient evidence to conclude that the average College tuition for a law degree costs at least thirty five thousand dollars.
The first choice is correct trust meh. Have a nice day/night !
