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Anastasy [175]
3 years ago
8

At which position in its orbit was the Moon located during the 2015 supermoon total lunar eclipse?

Chemistry
2 answers:
Novay_Z [31]3 years ago
7 0
On September 27, 2015, a rare total lunar eclipse of a supermoon occurred. A supermoon occurs when the entire lighted half of the Moon faces Earth (full Moon phase) and the Moon is at its closest point to Earth in its orbit.
Mice21 [21]3 years ago
6 0

Answer:

On September 27, 2015

Explanation:

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write down the balanced chemical equation of the reaction that takes place between iron and concentrated sulphuric acid​
pishuonlain [190]

Answer:

2Fe + 3H2SO4 → Fe2(SO4)3 + 3H2

Explanation:

Iron is a metallic element with chemical symbol, Fe while concentrated sulphuric acid is a chemical compound with chemical formula, H2SO4. Both are involved in a chemical reaction as follows:

Fe + H2SO4 → Fe2(SO4)3 + H2

However, this reaction is not balanced as the number of moles of each atom in both the reactants and product side is not equal. To balance the equation, we have to ensure that each number of atom is equal. The balanced equation are as follows:

2Fe + 3H2SO4 → Fe2(SO4)3 + 3H2

5 0
3 years ago
Write the chemical equation of in elements
Scilla [17]

Answer : The balanced chemical reaction will be:

CuO+H_2SO_4\rightarrow CuSO_4+H_2O

Explanation :

As per question when copper(II) oxide react with sulfuric acid then it gives copper(II) sulfate and water.

This reaction is known as double displacement reaction in which cation of two reactants exchange their places to give two different products.

The balanced chemical reaction will be:

CuO+H_2SO_4\rightarrow CuSO_4+H_2O

8 0
4 years ago
THIS IS A THREE PART QUESTION IF YOU CAN HELP IT WOULD BE REALLY APPRECIATED SO I DONT FAIL.
Nostrana [21]

Answer:

1. B = 1.13M

2. A. 8.46%

3. D = 0.0199

Explanation:

1. Molarity of a a solution = number of moles of solute/ volume of solution in L

Number of moles of solute = mass of solute/molar mass of solute

Molar mass of NaC₂H₃O₂ = 82 g/mol, mass of NaC₂H₃O₂ = 245 g

Number of moles of NaC₂H₃O₂ = 245 g / 82 g/mol = 2.988 moles

Molarity of solution = 2.988 mols/ 2.65 L = 1.13 M

2. Percentage by mass of a substance = mass of substance /mass of solution × 100%

Mass of 2.65 L of water = density × volume

Density of water = 1 Kg/L = 1000 g/L; volume of waterb= 2.65 L

Mass of water = 1000 g/L × 2.65 L = 2650 g

Mass of solution = mass of water + mass of solute = 245 + 2650 =2895 g

Percentage by mass of NaC₂H₃O₂ = 245/2895 × 100% = 8.46%

3. Mole fraction of NaC₂H₃O₂ = moles of NaC₂H₃O₂/moles of solution

Moles of water = mass /molar mass

Mass of water = 2650 g; molar mass of water = 18 g/mol

Moles of water = 2650 g / 18 g/mol = 147.222 moles

Moles of solution = moles of solute + moles of water = 147.222 + 2.988 = 150.21

Moles of NaC₂H₃O₂ =2.988 moles

Moles fraction of NaC₂H₃O₂ =2.988/150.21 = 0.0199

6 0
3 years ago
Which physical property of matter can be expressed numerically in SI units?
pantera1 [17]
Mass is the physical property of matter can be expressed numerically in SI units. 
3 0
4 years ago
Calculate the percent ionization of nitrous acid in a solution that is 0.230 M in nitrous acid. The acid dissociation constant o
djyliett [7]
Ok first, we have to create a balanced equation for the dissolution of nitrous acid.

HNO2 <-> H(+) + NO2(-)

Next, create an ICE table

           HNO2   <-->  H+        NO2-
[]i        0.230M          0M       0M
Δ[]      -x                   +x         +x
[]f        0.230-x          x           x

Then, using the concentration equation, you get

4.5x10^-4 = [H+][NO2-]/[HNO2]

4.5x10^-4 = x*x / .230 - x

However, because the Ka value for nitrous acid is lower than 10^-3, we can assume the amount it dissociates is negligable, 

assume 0.230-x ≈ 0.230

4.5x10^-4 = x^2/0.230

Then, we solve for x by first multiplying both sides by 0.230 and then taking the square root of both sides.

We get the final concentrations of [H+] and [NO2-] to be x, which equals 0.01M.

Then to find percent dissociation, you do final concentration/initial concentration.

0.01M/0.230M = .0434 or 

≈4.34% dissociation.
8 0
3 years ago
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