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Volgvan
3 years ago
11

The sixth-grade class is raising money to have a

Mathematics
1 answer:
VMariaS [17]3 years ago
3 0

Answer:

There is a 10 percent increase

You might be interested in
What's the recursive formula of the geometric sequence below?
yKpoI14uk [10]

Answer:

Hey there!

We have an=a1(r^n-1), which is the formula for a geometric sequence.

The common ratio is 3, and 2 is the 1st term.

Thus, we have a1=2(3)^(n-1)

Hope this helps :)

5 0
3 years ago
What is the median and mode
viktelen [127]
Median is the middle number

60, 60, 65, 70, 70, 85, 90

70 is your median

mode is the number(s) that show up the most
60 and 70 is your mode, since they show up twice (one more than the others)

Range is largest number minus the smallest
90 - 60 = 30, 30 is your range

Mean is all the numbers added together divided by the number of numbers there are 
60 + 90 + 65 + 70 + 70 + 85 + 60 = 500
500/7 = 71.42
Mean = 71.42

hope this helps
5 0
3 years ago
What is the value of x?
melisa1 [442]

Answer:

x=71

Step-by-step explanation:

38+x+x=180

x+x=142

2x=142

x=71

3 0
3 years ago
The drug Viagra comes in a quantity of 30 tablets with an AWP of $900. The pharmacy has an agreement with the supplier to purcha
MrRissso [65]

The profit of  5103.5 by making a prescription for 6 tablets.

<h3>What is percentage?</h3>

Percentage, a relative value indicating hundredth parts of any quantity.

The drug Viagra comes in a quantity of 30 tablets with an AWP of $900.

The insurer is willing to pay the AWP less 5% plus a $2.50

900/TAB = X 30 TABS  =$27000

27000 * (0.05)= $1350

27000-1350.00

=$25650 + $2.50

=25652.5 for 30 tablets

For 6 tablets,

= (25652.5 / 30)*6

= 5103.5

Learn more about percentage here:

brainly.com/question/14695543

#SPJ1

5 0
2 years ago
Ana escribe conjuntos de cinco enteros positivos consecutivos con la siguiente propiedad: La suma de tres de los números es tan
Keith_Richards [23]

Answer:

a) 1.

Step-by-step explanation:

Supongamos que el primer número entero positivo es a tal que a ∈ Z⁺.

Luego, el conjunto de los cinco enteros positivos se puede expresar como

A = {a; a+1; a+2; a+3; a+4}

Dada la condición del problema, se debe cumplir que

a + (a+1) + (a+2) = (a+3) + (a+4)

⇒  3a + 3 = 2a + 7

Resolviendo la ecuación resulta

a = 4

Luego, el conjunto A nos resulta

A = {4; 5; 6; 7; 8}

Puede concluirse que sólo un conjunto cumple con esta condición.

5 0
3 years ago
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