Answer:
22 radio advertisements will be used.
Explanation:
<u>Note</u>: A similar complete question is as follow as the question provided is incomplete <em>"A company has $11,970 available per month for advertising. Newspaper ads cost $110 each and can't run more than 25 times per month. Radio ads cost $410 each and can't run more than 32 times per month at this price. Each newspaper ad reaches 5950 potential customers, and each radio ad reaches 7100 potential customers. The company wants to maximize the number of ad exposures to potential customers. Use n n for number of Newspaper advertisements and r r for number of Radio advertisements . Maximize P"</em>
Number of potential customers that can be reached due to each dollar spent in newspaper advertising = 5950 / 110 = 54.09
Number of potential customers that can be reached due to each dollar spent in Radio advertisements = 7100 / 410 = 17.32.
As the number of potential customers reached by each dollar spent is more from the newspaper advertising, we will use all the newspaper advertising opportunities before going for the radio advertisements. So, we will choose to have 25 newspaper advertisements in the month.
The cost of 25 newspaper advertisements = 25*110 = $2750.
Amount left = $11970 - $2750 = $9220.
Number of radio advertisements possible in this budget = 9220 / 410 = 22.48
Hence, 22 radio advertisements will be used.
