Answer:
1. 15
2. 8
Step-by-step explanation:
The two sequence are geometric progression GP, because they follow a constant multiple (common ratio)
The nth term of a GP is;
Tn = ar^(n-1)
Where;
a = first term
r = common ratio
For the first sequence;
The common ratio r is
r = T3/T2 = 540/90 = 6
r = 6
T2 = ar^(2-1) = ar
T2 = 90 = ar
Substituting the values of r;
90 = a × 6
a = 90/6
a = 15
First term = 15
2. The sam method applies here.
Common ratio r = T3/T2 = 128/32 = 4
r = 4
T2 = ar^(2-1) = ar
T2 = 32 = ar
Substituting the values of r;
32 = a × 4
a = 32/4
a = 8
First term = 8
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Answer:
(b)
P = [4(4a + 3b]/(2a + b)
Step-by-step explanation:
P = 2L + 2W
P = [2(5a + 4b) + 2(3a + 2b)]/(2a + b)
P = [10a + 8b + 6a + 4b]/(2a + b)
P = [16a + 12b]/(2a + b)
P = [4(4a + 3b]/(2a + b)
