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2 years ago

If I made $1,000 every 2 minutes, how much would I have in an hour?

Mathematics

2 answers:

Sunny_sXe [5.5K]2 years ago

7 0

Answer:

1 hour=60min

60min=60/2×1000

=$30000

Step-by-step explanation:

nika2105 [10]2 years ago

4 0

Answer:

$30,000

Step-by-step explanation:

There are 60 minutes in an hour. There are 30 two minutes in 60 minutes. 30*1,000 = 30,000.

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Adams, Greensburg, Middletown, and Waldron are four towns in Indiana on a nearly straight highway. If the highway is represented

andrey2020 [161]

Answer:

W, M, A and G

Step-by-step explanation:

The question is not correct, the correct question is Adams, Greensburg, Middletown, and Waldron are four towns in Indiana on a nearly straight highway. If the highway is represented by a line, the towns can be represented by four points: A, G, M, and W. Given that MG + WM = WG and MA = MG - AG determine the proper order of the four towns.

Answer: The line segment addition postulate states that for a line segment AC with point B which lines on AC, then this equation holds:

AB + BC = BC

Given that MG + WM = WG, this means that point M lies between the segment WG.

Also, MA = MG - AG

MA + AG = MG, hence point A lies between segment MG

Therefore the order of the points is W, M, A and G

8 0

2 years ago

Sketch the domain D bounded by y = x^2, y = (1/2)x^2, and y=6x. Use a change of variables with the map x = uv, y = u^2 (for u ?

cluponka [151]

Under the given transformation, the Jacobian and its determinant are

$\begin{cases}x=uv\\y=u^2\end{cases}\implies J=\begin{bmatrix}v&u\\2u&0\end{bmatrix}\implies|\det J|=2u^2$

so that

$\displaystyle\iint_D\frac{\mathrm dx\,\mathrm dy}y=\iint_{D'}\frac{2u^2}{u^2}\,\mathrm du\,\mathrm dv=2\iint_{D'}\mathrm du\,\mathrm dv$

where $D'$ is the region $D$ transformed into the $u$ - $v$ plane. The remaining integral is the twice the area of $D'$ .

Now, the integral over $D$ is

$\displaystyle\iint_D\frac{\mathrm dx\,\mathrm dy}y=\left\{\int_0^6\int_{x^2/2}^{x^2}+\int_6^{12}\int_{x^2/2}^{6x}\right\}\frac{\mathrm dx\,\mathrm dy}y$

but through the given transformation, the boundary of $D'$ is the set of equations,

$\begin{array}{l}y=x^2\implies u^2=u^2v^2\implies v^2=1\implies v=\pm1\\y=\frac{x^2}2\implies u^2=\frac{u^2v^2}2\implies v^2=2\implies v=\pm\sqrt2\\y=6x\implies u^2=6uv\implies u=6v\end{array}$

We require that $u>0$ , and the last equation tells us that we would also need $v>0$ . This means $1\le v\le\sqrt2$ and $0$ , so that the integral over $D'$ is

$\displaystyle2\iint_{D'}\mathrm du\,\mathrm dv=2\int_1^{\sqrt2}\int_0^{6v}\mathrm du\,\mathrm dv=\boxed6$

4 0

2 years ago

-4x -6 = 3 - 5x Solve for x pls

ycow [4]

Answer:

x = 9

Explanation:

-4x - 6 = 3 - 5x

Add 6 to both sides

-4x - 6 + 6 = 3 - 5x + 6

-4x = -5x + 9

Add 5x to both sides

-4x + 5x = -5x + 9 + 5x

x = 9

- PNW

4 0

2 years ago

Read 2 more answers

Given three consecutive integers with a sum of four times the second number, write an algebraic equation for this situation

Black_prince [1.1K]

Define x:

Let the first number be x.

1st number = x
2nd number = x + 1
3rd number = x + 2

Construct equation:
x + x + 1 + x + 2 = 4(x + 1)
3x + 3 = 4(x + 1)

Answer: 3x + 3 = 4(x + 1)

5 0

3 years ago

What is the value of the expression p – 26 when p = 12?

serious [3.7K]

The answer is -14 cuz if u subtract 16 from 26 it will have nothing cuz there I s not enough so it will go to a negative 14 in order to subtract it all the way

HOPE U UNDERSTOOD:)) >_<

7 0

3 years ago