The particle has constant acceleration according to
Its velocity at time is
Then the particle has position at time according to
At at the point (3, 6, 9), i.e. when , it has speed 8, so that
We know that at some time , the particle is at the point (5, 2, 7), which tells us
and in particular we see that
and
Then
That is, there are two possible initial velocities for which the particle can travel between (3, 6, 9) and (5, 2, 7) with the given acceleration vector and given that it starts with a speed of 8. Then there are two possible solutions for its position vector; one of them is
For this problem the figure below shows the representation of a student who pulls on a 20kg box. We know this variables:
Weight of the box = 20kg
Force used by the student to pull on the box = 50N (This is the tension T)
Angle relative to the horizontal = 45 degrees
Aceleration of the box =
The figure also shows the Free-Body diagram, Applying Newton's Second Law we can find the equation for this diagram, related to the x-axis as:
Isolating
:
<span>That is the friction force on the box.</span>
Let v = the running speed
After running at constant speed for 26 min, the distance traveled is
d = (v m/min)*(26 min) = 26v m
Because there are 1500 m to go, the distance traveled is
10000 - 1500 = 8500 m
The running speed is
v = (8500 m)/(26 min) = 326.9 m/min
In km/h, the speed is
v = (0.3269 km/min)*(60 min/h) = 19.6 km/h
Answer: The running speed is 19.6 km/h
Answer:
Magnitude of the acceleration due to gravity on the planet = 2.34 m/s²
Explanation:
Time period of simple pendulum is given by
, l is the length of pendulum, g is acceleration due to gravity value.
We can solve acceleration due to gravity as
Here
Length of pendulum = 1.20 m
Pendulum executes simple harmonic motion and makes 100 complete oscillations in 450 s.
Period,
Substituting
Magnitude of the acceleration due to gravity on the planet = 2.34 m/s²
10Km South. Displacement is the total distance the subject is from the starting point.