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Sveta_85 [38]
3 years ago
5

Which quantity must be the same for two bodies in thermal equilibrium?

Physics
1 answer:
ZanzabumX [31]3 years ago
6 0
C. Temperature of the 2 bodies are the same
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Real world situation to explain the relationship between work and power
In-s [12.5K]
-- You and your partner both get the same job to do:

Each of you gets a pallet of bricks, and you have to
put the bricks up on the bed of a truck, by hand.
Both pallets have the same number of bricks.

The pallet is way too heavy to lift, so you both cut the bands
that hold the bricks, and you lift the bricks from the pallet onto
the truck, by hand, two or three or four bricks at a time.

-- You get your pallet of bricks onto the truck in 45 minutes.

-- Your partner gets his pallet of bricks onto the truck in 3 days.

-- Work = (force) times (distance).

    You and your partner both lifted the same amount of weight
     up to the same height.  You both did the same amount of work.

-- Power = (work done) divided by (time it takes to do the work) .

  
Your partner took roughly 96 times as long as you took
   to do the same amount of work. 
   You did it faster.  He did it slower.
   You produced more power.  He produced less power. 
5 0
4 years ago
Which of these statements about mixtures is true? (2 points)
zavuch27 [327]

Answer:A

Explanation:

6 0
3 years ago
Read 2 more answers
A mass spectrometer is being used to separate common oxygen-16 from the much rarer oxygen-18, taken from a sample of old glacial
Mashcka [7]

Answer: 0.076 m

Explanation:

Magnetic force= centripetal force;

F(B) = F(c) --------------------------(1)

Bqv= mv^2/R---------------------(2)

Where B= magnetic field,q= charge, = mass, R= radius of the circular path.

Radius of the circular path,R= mv/qB.

Mass of oxygen-16 is 2.66e−26kg, and they are singly charged = 18/16(mass ratio= 18:16)

18/16 × (2.26 × 10^ -26 kg)

= 2.99 × 10^26 kg

∆d=2r(18)-2r(16)-----------------(3)

r(18) is the radius of mass of oxygen-18,

r(16) is the radius of mass of oxygen-16.

From the question, v= 3.7×10^6 m/s, q= 1.6×10^-9 C.

From equation (2) above we have;

R= MV/qB------------------------(4)

This equation (4) is used in solving for the distance between the two.

Solving;∆d=2r(18)-2r(16)

∆d = 2[m(18) - m(16)] v/ qB

M(18)-m(16) =(2.99-2.66)× 10^-26:

qB= 1.6×10^-19×2 = 3.2×10^-19

= (2.99-2.66)× 10^-26/ 3.2× 10^-19

= 0.076 m

7 0
3 years ago
If you have a final velocity of 50 m/s and travelled for 120 seconds. What
zhuklara [117]

Answer:

a=v-u/t

Explanation:

use this formula and initial velocity is 0

5 0
2 years ago
Read 2 more answers
Please hurry please
Ghella [55]

Answer:

0.765m

Explanation:

gravitational potential energy GPE = mass * acceleration due to gravity * height

Given

GPE = 30Joules

Mass m = 4kg

acceleration = 9.8m/s²

Required

Height h

From the formula

h = GPE/mg

h = 30/4(9.8)

h = 30/39.2

h = 0.765m\

Hence the height of the counter is 0.765m

4 0
3 years ago
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