Answer: c
Step-by-step explanation:
The given equation is
where h is the height, in feet, of a ball and t is the time, in seconds.
<u>Part a: The height of the ball when t = 2 seconds:</u>
The height of the ball above the ground 2 seconds after it is released can be determined by substituting t= 2 in the equation
, we get;

Simplifying the terms, we get;


Thus, the height of the ball after 2 seconds is 100 feet.
<u>Part b: The height of the ball when t = 4 seconds:</u>
The height of the ball above the ground 4 seconds after it is released can be determined by substituting t = 4 in the equation
, we get;

Simplifying the terms, we get;


Thus, the height of the ball after 4 seconds is 68 feet.
Answer:
y = -5/2x - 13
Step-by-step explanation:
First, we have to find the slope of the original equation
Subtract 5x from both sides
5x + 2y = 1
- 5x - 5x
2y = -5x + 1
Divide both sides by 2
2y/2 = (-5x + 1)/2
y = -5/2x + 1/2
The slope of this equation is -5/2, so -5/2 has to be in our new parallel equation
y = -5/2x + b
Plug in the given x and y
-3 = -5/2(-2) + b
-3 = 10 + b
Subtract 10 from both sides
-3 = 10 + b
- 10 - 10
b = -13
This makes our equation: y = -5/2x - 13
Answer:
3139291489
Step-by-step explanation:
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