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3 years ago

10

on day 1 a patient measures 5 feet and 11 inches tall. after 4 days of stretching the patient measures 5 feet and 11 inches tall

. What is the slope and is it negative or positive?

1 answer:

Vinvika [58]3 years ago

5 0

Answer:

slope is zero

Step-by-step explanation:

zero slope is neither positive or negative; it indicates no change whatsoever

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Find the degree of the polynomial: 5ab^3−7a^5c^2−5

alexandr402 [8]

Answer:

I think its 5

Step-by-step explanation:

6 0

3 years ago

Help PLEASE this is 99 points what is the prime factorization of 270?

serg [7]

270 = 27 * 10

= 3*9 * 5*2

= 3 * 3*3 * 5*2

in order from smallest to largest

2*3*3*3 *5

5 0

3 years ago

Read 2 more answers

Which of the following is the least? A. 0.105 B. 0.501 C. 0.015 D. 0.15

Naddika [18.5K]

C is the least that is beause it is .015 which is smaller than 0.15

8 0

3 years ago

vivado [14]

Answer:

33, 792

Step-by-step explanation:

first convert the 8 miles to feet because our answers are in feet.

1 mile= 5280 feet

therefore 8 miles= 5280×8

= 42240

Dale and son covered 4/5 of the 42240 feet

= 4/5×42240

= 33,782 feet

4 0

1 year ago

Erica is a sheep farmer. She is having a problem with wolves attacking the flock. She starts with an initial 200 sheep and notic

Free_Kalibri [48]

The equation for the situation is $y=200(\frac{2}{3})^{x}$

It will take around 9 years for her to have around 5 sheep

Step-by-step explanation:

The exponential decay growth/decay equation is $y=a(b)^{x}$ , where

a is the initial value
b is the growth/decay factor
If b > 1, then it is a growth factor
If 0 < b < 1, then it is a decay factor

Erica is a sheep farmer. She is having a problem with wolves attacking the flock. She starts with an initial 200 sheep and notices that the population is two-thirds of the previous year

∵ The population is decreased

∴ The equation is decay

∵ The population is two-thirds of the previous year

∴ The decay factor is $\frac{2}{3}$

∵ She starts with an initial 200 sheep

∴ the initial value is 200

∵ The decay equation is $y=a(b)^{x}$ , where y represent the

population in x years

∵ a = 200

∵ b = $\frac{2}{3}$

∴ $y=200(\frac{2}{3})^{x}$

The equation for the situation is $y=200(\frac{2}{3})^{x}$

∵ The population after x years is around 5 sheep

- Substitute y by 5 to find x

∵ $5=200(\frac{2}{3})^{x}$

- Divide both sides by 200

∴ $0.025=(\frac{2}{3})^{x}$

- Insert ㏒ for both sides

∴ $log(0.025)=log(\frac{2}{3})^{x}$

∴ $log(0.025)=xlog(\frac{2}{3})$

- Divide both sides by $log(\frac{2}{3})$

∴ 9.098 = x

∴ x is around 9 years

It will take around 9 years for her to have around 5 sheep

Learn more:

You can learn more about the equation in brainly.com/question/10666510

#LearnwithBrainly

8 0

3 years ago