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Sophie [7]
3 years ago
9

A bank account has an initial deposit of $18,000. After 5 years, the bank account

Mathematics
1 answer:
ivolga24 [154]3 years ago
5 0

Answer:

7.63%

Step-by-step explanation:

26000 = 18000 (x)⁵

Divide both sides by 18000

1.4444444444 = x⁵

Raise both sides to the (1/5) power

1.4444444444^(1/5) = x

1.0763169225 = x

interest = x - 1

interest = 0.0763169225

Appox interest rate = 7.63%

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The same as has greater then less than plz anwser I am struggling
xeze [42]
For each power of ten , the number of zeros written in the product is the same as the number of exponents.
3 0
3 years ago
You are going to roll two dice. Let the variable x = the sum of the numbers rolled. What is the probability that x = 9 ?
Vladimir79 [104]

The  first cube can land in any one of  6  ways.
The  second cube can land in any one of  6  ways.
Total number of ways that  2 dice can land = (6 x 6) = 36 ways.

For any of these ways, the sum of the numbers rolled is  9 :

3, 6
4, 5
5, 4
6, 3

There are  4  ways to roll a 9, out of a total of  36  ways that
the dice can land.  So the probability of rolling a  9  is

       4 / 36  =  1 / 9  =  <em>11-1/9 percent</em>


7 0
3 years ago
If mLABC = (2x + 4)º, m_DEF= (3x – 5)°, and ABC and
Harrizon [31]

Answer:

-5x-1

Step-by-step explanation:

4 0
3 years ago
The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d
kozerog [31]

Answer: 49.85%

Step-by-step explanation:

Given : The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped ( normal distribution ) and has a mean of 61 and a standard deviation of 9.

i.e.  \mu=61 and \sigma=9

To find :  The approximate percentage of lightbulb replacement requests numbering between 34 and 61.

i.e. The approximate percentage of lightbulb replacement requests numbering between 34 and 34+3(9).

i.e. i.e. The approximate percentage of lightbulb replacement requests numbering between \mu and \mu+3(\sigma). (1)

According to the 68-95-99.7 rule, about 99.7% of the population lies within 3 standard deviations from the mean.

i.e. about 49.85% of the population lies below 3 standard deviations from mean and 49.85% of the population lies above 3 standard deviations from mean.

i.e.,The approximate percentage of lightbulb replacement requests numbering between \mu and \mu+3(\sigma) = 49.85%

⇒ The approximate percentage of lightbulb replacement requests numbering between 34 and 61.= 49.85%

4 0
3 years ago
Which of these strategies would eliminate a variable in the system of equations?
KATRIN_1 [288]
Answer: A and B


Explanation: I’ll use A as an example. When you multiply the bottom equation by -3/2, the equation becomes: -9x+6y=-3. Then, proceed to add the equations. Look at X and Y in both equations: do the Y variables in both equations equal to 0 when added together? Yes, because -6y+6y=0! Therefore, you can eliminate y in these two equations.




Hope that’s helps シ
6 0
3 years ago
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