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masha68 [24]
2 years ago
8

Solve for x please thanks​

Mathematics
1 answer:
N76 [4]2 years ago
6 0

Answer:

32

Step-by-step explanation:

So, lets go over what we know:

The equation to find x is the same on both sides.

Now, lets find this equation:

So, the total area of the two lines on the left side of the triangle are 24.

Lets first subtract the first line from the total of the two lines to find the value of the second line:

24-3

=

21.

Now that we know the value of the 2nd line is 21. lets divide it by the first line(3) to find the scale factor:

21/3

=

7

So the scale factor is 7!

Lets plug this in for x.

We know that the first line is 4.

The second line is 7x bigger than 4.

So we can calculate this as:

7x4

=

28

So x is 28!

This is your answer!

Hope it helps! :)

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The answer to the question

4 0
3 years ago
The length of a rectangle is five times its width. If the perimeter is at most 96 centimeters, what is the greatest possible val
Anvisha [2.4K]
Answer is in the attachment below.

7 0
2 years ago
Help me find the solution set for 8x-3=2(x-1/2)
daser333 [38]
8x -3 = 2(x-1/2)
⇒ 8x -3= 2x -2*(1/2)
⇒ 8x -3 = 2x -1
⇒ 8x -2x= -1+ 3
⇒ 6x = 2
⇒ x= 2/6
⇒ x= 1/3

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6 0
3 years ago
A cylinder and a cone both have radius of 6". The height of the cone is 12". The height of the cylinder is 6". Which has the gre
Shkiper50 [21]

Answer:

cylinder has greatest volume

Step-by-step explanation:

solution

given,

radius of cylinder(r)=6cm

height of cylinder (h)=6cm

we know,

volume of cylinder=πr^2h

=22÷7×6×6×6

=4752÷7

=678.857cm^3

radius of cone(r)=6cm

height of cone(h)=12cm

we know,

volume of cone=1÷3πr^3

= 1÷3×22÷7×6×6×6

= 4752÷21

=226.2857cm^3

as a result,cylinder has greatest volume

4 0
2 years ago
Can someone plz help me. How can you find the inequalities of 11/15 and 5/7. Next 5/9 and 7/13. Next 11/15 and 5/7. Lastly 5/9 a
LekaFEV [45]
To make this a little clearer, let's give the pairs of inequalities the same denominator:

<span>Question 1: 
</span>\frac{11}{15} ? \frac{5}{7}
First, apply the common denominator to the first fraction:
(\frac{11}{15})7 \\  \frac{11}{15} *  \frac{7}{7}  \\  \frac{11*7}{15*7}  \\  \frac{77}{105}
Do the same for the second:15( \frac{5}{7}) \\  \frac{5}{7}* \frac{15}{15} \\  \frac{5*15}{7*15}  \\  \frac{75}{105}
Nest, compare the two fractions:
\frac{77}{105} \ \textgreater \   \frac{75}{105}
Therefore:
\frac{11}{15} > \frac{5}{7}
<span>
Question Two:</span>
\frac{5}{9} ? \frac{7}{13}
Apply the common denominator to fraction one:
13( \frac{5}{9}) \\  \frac{5}{9} * \frac{13}{13}  \\  \frac{5*13}{9*13}  \\  \frac{65}{117}
Fraction two:
9(\frac{7}{13}) \\  \frac{7}{13} *  \frac{9}{9}  \\  \frac{7*9}{13*9}  \\  \frac{63}{117}
Evaluate:
\frac{65}{117} > \frac{63}{117}
Therefore:
<span>\frac{5}{9} > \frac{7}{13}
</span>
Hope this helps!
5 0
3 years ago
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