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Nadya [2.5K]
2 years ago
11

A sample of 12 measurements has a mean of 16.5, and a sample of 15 measurements has a mean of 18.6. Find the mean of all 27 meas

urements
Mathematics
1 answer:
Wewaii [24]2 years ago
4 0

Answer: 17.67

Step-by-step explanation:

Given

Sample  of 12 measurements has a mean of 16.5 and

a sample of 15 measurements has a mean of 18.6

Take \bar{x_1},n_1 be the mean and no of measurements

and \bar{x_2},n_2 be the mean and no of measurements in second case

\therefore \bar{x_1}=\dfrac{\sum a_1}{n_1}\\\\\Rightarrow \sum a_1=\bar{x_1}\times n_1\\\\\Rightarrow \sum a_1=198\quad \ldots(1)

Similarly,

\therefore \bar{x_2}=\dfrac{\sum a_2}{n_2}\\\\\Rightarrow \sum a_2=\bar{x_2}\times n_2\\\\\Rightarrow \sum a_2=279\quad \ldots(2)

Mean of 27 measurements

\Rightarrow \bar{x_3}=\dfrac{\sum a_1+\sum a_2}{n_1+n_2}\\\\\Rightarrow \bar{x_3}=\dfrac{198+279}{12+15}\\\\\Rightarrow \bar{x_3}=\dfrac{477}{27}\\\\\Rightarrow \bar{x_3}=17.67

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Answer:

B) 42 units squared

Step-by-step explanation:

12 * 7 = 84

84 / 2 = 42

<em><u>Hope this helped! Have a nice day! Plz mark as brainliest!!!</u></em>

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How many times smaller is 2 × 10^-10 than 4 × 10^-5
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Answer:

200,000

Step-by-step explanation:

To find how many times smaller is smaller number than greater number, divide greater number by smaller number.

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Then

\dfrac{\text{Greater number}}{\text{Smaller number}}\\ \\=\dfrac{4\times 10^{-5}}{2\times 10^{-10}}\\ \\=\dfrac{4}{2}\times \dfrac{10^{-5}}{10^{-10}}\\ \\=2\times \dfrac{1}{10^{-5}}\\ \\=2\times 10^5\\ \\=2\times 100,000\\ \\=200,000

7 0
3 years ago
University officials say that at least 70% of the voting student population supports a fee increase. If the 95% confidence inter
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Answer:

The interval estimate is above 70%, so infer that it will be supported.

Step-by-step explanation:

The evidence that 95% confidence interval estimating the proportion of students supporting the fee increase is [0.75, 0.85] supports university officials' claim that at least 70% of the voting student population supports a fee increase.

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Let Upper A equals left bracket Start 2 By 2 Matrix 1st Row 1st Column negative 2 2nd Column 4 2nd Row 1st Column 1 2nd Column 3
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Answer:

See explanation

Step-by-step explanation:

Given:

A=\left[\begin{array}{cc}-2&4\\1&3\end{array}\right]

B=\left[\begin{array}{cc}-2&1\\3&7\end{array}\right]

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B. Find BA:

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