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4 years ago

What is the difference in a length between a 1 1/4 and a 3/4 inch button

Mathematics

1 answer:

Tasya [4]4 years ago

8 0

Answer:

Step-by-step explanation:

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How do you write 4/6 as a unit fraction

lawyer [7]

Answer:

1/6

Step-by-step explanation:

1/6 + 1/6 + 1/6 + 1/6 = 4/6. A unit fraction has a numerator of 1 so since 4 is the numerator in 4/6 You should add 1/6 four times.

Hope this helps!

Brain-List?

3 0

3 years ago

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Please help! Will mark brainlyest. :)

Elden [556K]

Answer:

Step-by-step explanation:

base times hight times times 1/2

24X4X1/2

7 0

2 years ago

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Determine if A^-1 C=C A^-1 Given: A^-1 C=

ryzh [129]

CA ⁻¹ is undefined because there are more columns in A ⁻¹ than there are rows in C.

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3 years ago

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Multiply 6+2i and it’s conjugate. Simplify. Help me please ASAP

vlabodo [156]

Answer:

Step-by-step explanation:

(6 + 2i)(6 – 2i) = 36 – 4i²

= 36 + 4 = 40

7 0

4 years ago

1. if csc β = 7/3 and cot β = - 2√10 / 3, Find sec β

slava [35]

Step-by-step explanation:

$\tan \beta = \frac{1}{ \cot \beta } = - \frac{3}{2 \sqrt{10} } = - \frac{3 \sqrt{10} }{20}$

$\csc \beta \tan \beta = \frac{1}{ \cos \beta } = \sec \beta$

Therefore,

$\sec \beta = ( \frac{7}{3} )( - \frac{3 \sqrt{10} }{20} ) = - \frac{7 \sqrt{10} }{20}$

$\csc y = \frac{1}{ \sin y} = - \frac{ \sqrt{6} }{2}$

$= > \sin y = - \frac{ \sqrt{6} }{3}$

Use the identity

$\cos y = \sqrt{1 - \sin ^{2} y} \: \: \: \: \: \: \: \: \: \: \: \\ = \sqrt{1 - {( - \frac{ \sqrt{6} }{3}) }^{2} } = - \frac{ \sqrt{3} }{3}$

We chose the negative value of the cosine because of the condition where cot y > 0. Otherwise, choosing the positive root will yield a negative cotangent value. Now that we know the sine and cosine of y, we can now solve for the tangent:

$\tan \beta = \frac{ \sin y}{ \cos y} =( - \frac{ \sqrt{6} }{3} )( - \frac{3}{ \sqrt{3} } ) = \sqrt{2}$

3. Recall that sec x = 1/cos x, therefore cos x = 5/6. Solving for sin x,

$\sin x = \sqrt{1 - \cos ^{2} x} = \sqrt{ \frac{11}{6} }$

Solving for tan x:

$\tan x = \frac{ \sin x}{ \cos x} = (\frac{ \sqrt{11} }{ \sqrt{6} } )( \frac{6}{5} ) = \frac{ \sqrt{66} }{5}$

5 0

3 years ago