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Mila [183]
3 years ago
15

Modify the sentence-generator program of Case Study so that it inputs its vocabulary from a set of text files at startup. The fi

lenames are nouns.txt, verbs. txt, articles.txt, and prepositions.txt. (Hint: Define a single new function, getWords. This function should expect a filename as an argument. The function should open an input file with this name, define a temporary list, read words from the file, and add them to the list. The function should then convert the list to a tuple and return this tuple. Call the function with an actual filename to ini- tialize each of the four variables for the vocabulary.)Case Study: Generating Sentences code:import randomarticles = ("A", "THE")nouns = ("BOY", "GIRL", "BAT", "BALL")verbs = ("HIT", "SAW", "LIKED")prepositions = ("WITH", "BY")def sentence():return nounPhrase() + " " + verbPhrase()def nounPhrase():return random.choice(articles) + " " + random.choice(nouns)def verbPhrase():return random.choice(verbs) + " " + nounPhrase() + " " + \prepositionalPhrase()def prepositionalPhrase():return random.choice(prepositions) + " " + nounPhrase()def main():number = int(input("Enter the number of sentences: "))for count in range(number):print(sentence())if __name__ == "__main__":main()

Computers and Technology
1 answer:
Snezhnost [94]3 years ago
6 0

Answer:

Go to explaination for the program code.

Explanation:

Before running the program you need to have these files created like below in your unix box.

Unix Terminal> cat nouns.txt

BOY

GIRL

BAT

BALL

Unix Terminal> cat articles.txt

A

THE

Unix Terminal> cat verbs.txt

HIT

SAW

LIKED

Unix Terminal> cat prepositions.txt

WITH

BY

Unix Terminal>

Code:

#!/usr/local/bin/python3

import random

def getWords(filename):

fp = open(filename)

temp_list = list()

for each_line in fp:

each_line = each_line.strip()

temp_list.append(each_line)

words = tuple(temp_list)

fp.close()

return words

articles = getWords('articles.txt')

nouns = getWords('nouns.txt')

verbs = getWords('verbs.txt')

prepositions = getWords('prepositions.txt')

def sentence():

return nounPhrase() + " " + verbPhrase()

def nounPhrase():

return random.choice(articles) + " " + random.choice(nouns)

def verbPhrase():

return random.choice(verbs) + " " + nounPhrase() + " " + prepositionalPhrase()

def prepositionalPhrase():

return random.choice(prepositions) + " " + nounPhrase()

def main():

number = int(input('Enter number of sentences: '))

for count in range(number):

print(sentence())

if __name__=='__main__':

main()

kindly check attachment for code output and onscreen code.

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(b) 3,407,040 plates

(c) 6,084,000 plates

Explanation:

The very first thing to note about this question is the number of characters involved in the license plate format (6 characters in this case; 2 letters and 4 numbers). The letters come first and then the numbers follow.

There are a total of 26 possible letters (A-Z) and 10 possible numbers (0 - 9) that can be chosen. We can then proceed to the first question;

(a) Here, the total number of possible plates is to be determined. This is done as follows:

Character 1 (Letter): There are 26 possible letters

Character 2 (Letter): There are 26 possible letters

Character 3 (number): There are 10 possible numbers

Character 4 (number): There are 10 possible numbers

Character 5 (number): There are 10 possible numbers

Character 6 (number): There are 10 possible numbers

So, total number of different plates will be obtained by multiplying all the possibilities: 26 × 26 × 10 × 10 × 10 × 10 = 6,760,000 plates

(b) This second part puts a constraint on the usage of the numbers, unlike the question (a), where there was no constraint at all.

Since there is no constraint on the letters, we can write that:

Character 1 (Letter): There are 26 possible letters

Character 2 (Letter): There are 26 possible letters

For the first number as well, we can write:

Character 3 (number): There are 10 possible numbers

However, for the remaining characters, the possibilities will continually reduce by a value of 1, since we can not use a number that has been used before. So,

Character 4 (number): There are 9 possible numbers

Character 5 (number): There are 8 possible numbers

Character 6 (number): There are 7 possible numbers

So, total number of different plates will be: 26 × 26 × 10 × 9 × 8 × 7 = 3,407,040 plates

(c) Here, repetitions are allowed as in questions (a), but there can not be four zeros. This implies that the maximum number of zeros in any plate will be three. Thus, there will be maximum possibilities on all characters until the last one which will be constrained.

Character 1 (Letter): There are 26 possible letters

Character 2 (Letter): There are 26 possible letters

Character 3 (number): There are 10 possible numbers

Character 4 (number): There are 10 possible numbers

Character 5 (number): There are 10 possible numbers

Character 6 (number): There are 9 possible numbers

Total number of plates will therefore be: 26 × 26 × 10 × 10 × 10 × 9 = 6,084,000 plates.

7 0
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