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3 years ago

Locate and label at least five points on the coordinate plane that has an X coordinate of 6

1 answer:

8 0

Answer: you could use any point on the coordinate plane it just has to have the x coordinate for an example ( -1,6 ) is a point you could use .... I dunno maybe i'm wrong another helper you can use is symbolab it really helps me with my homework ... anyways let me know if I helped.

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In the figure below, mZAHE = (6x + 7)º

Andru [333]

Answer:

Step-by-step explanation:

∠AHE + ∠AHK = 180 {linear pair}

6x + 7 + 35 = 180

6x + 42 = 180

6x = 180 - 42

6x = 138

x = 138/6

x = 23

8 0

2 years ago

What is the simplest form of the expression 6x(x − 4) − 16x2 − (9x − 1)?

mario62 [17]

6•x•(x-4)-16•2-(9x-1)

4 0

2 years ago

What are the dimensions of the rectangle shown on the coordinate plane?

sveta [45]

The answer is (+2,6)

4 0

3 years ago

PLEASE HELP! I'll give 5 out of 5 stars, give thanks, and give as many points as I can.

Liula [17]

Answer:

$\boxed{\boxed{x=\dfrac{\pi}{3}\ \vee\ x=\pi\ \vee\ x=\dfrac{5\pi}{3}}}$

Step-by-step explanation:

$\cos(3x)=-1\iff3x=\pi+2k\pi\qquad k\in\mathbb{Z}\\\\\text{divide both sides by 3}\\\\x=\dfrac{\pi}{3}+\dfrac{2k\pi}{3}\\\\x\in[0,\ 2\pi)$

$\text{for}\ k=0\to x=\dfrac{\pi}{3}+\dfrac{2(0)\pi}{3}=\dfrac{\pi}{3}+0=\boxed{\dfrac{\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=1\to x=\dfrac{\pi}{3}+\dfrac{2(1)\pi}{3}=\dfrac{\pi}{3}+\dfrac{2\pi}{3}=\dfrac{3\pi}{3}=\boxed{\pi}\in[0,\ 2\pi)\\\\\text{for}\ k=2\to x=\dfrac{\pi}{3}+\dfrac{2(2)\pi}{3}=\dfrac{\pi}{3}+\dfrac{4\pi}{3}=\boxed{\dfrac{5\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=3\to x=\dfrac{\pi}{3}+\dfrac{2(3)\pi}{3}=\dfrac{\pi}{3}+\dfrac{6\pi}{3}=\dfrac{7\pi}{3}\notin[0,\ 2\po)$

7 0

3 years ago

Read 2 more answers

What is the estimate of 90/7 divided by 1 3/4

attashe74 [19]

Answer:

7×17/49

Step-by-step explanation:

90/7 × 4/7

90×4 / 7×7

360/49

7 17/49

6 0

2 years ago