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3 years ago

Ivan and kate live 40 miles apart. ivan leaves his house at 8:00

Mathematics

2 answers:

Angelina_Jolie [31]3 years ago

5 0

Answer:

Time at which the meet = 10:17:24 am

Step-by-step explanation:

Speed of Ivan = 12 mph

Speed of Kate = 16 mph

Total distance traveled = Initial separation = 40 miles

Ivan leaves his house at 8:00 a.m and Kate leaves her house at 9:30 a.m

If t is the time of catch up after Ivan starting, time taken by Kate is t - 1.5,

We have

Distance = Speed x Time

Total distance traveled = Distance traveled by Kate + Distance traveled by Ivan

40 = t x 12 + (t-1.5) x 16

40 = 28t - 24

28t = 64

t = 2.29 hours

So after 2.29 hours of Ivan's starting they meet,

Time = 8:00 am + 2.29 hours = 10:00 am + 0.29 x 60 minutes = 10:17am + 0.4 x 60 seconds = 10:17:24 am

Time at which the meet = 10:17:24 am

Kruka [31]3 years ago

3 0

Ivan DATA:
rate = 12 mph ; time = t hrs ; distance = 12t miles

Kate DATA:
rate = 16 mph ; time = t-(3/2) hrs ; distance = 16t - 24 miles

Equation:
12t + 16t-24 = 40 miles

28t = 64
time = 16/7 = 2hr 17 min
Ans: 8:00 + 2hr 17 min = 10:17AM

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