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Tcecarenko [31]
3 years ago
7

Consider the two expressions which statement is true?​

Mathematics
1 answer:
seraphim [82]3 years ago
6 0
The correct answer is: The two expressions are not equivalent because they do not always have the same value when any value is substituted for k.

Hope this helps!! :)
You might be interested in
What is the slope of the line perpendicular to the segment with endpoints (2,0) and (-6,3)?
r-ruslan [8.4K]

Answer:

A line that passes (2, 0) and (-6, 3) has slope:

S1 = (-6 -2)/(3 - 0) = -4/3

Another line that is perpendicular with above line has slope:

S2 = -1/S1 = -1/(-4/3) = 3/4

=> Option B is correct

Hope this helps

:)

3 0
3 years ago
Would love some help
natali 33 [55]
<h3>Answer: 90 cubic meters</h3>

Each triangle has a base of 10 and height of 3.6

area of triangle = 0.5*base*height = 0.5*10*3.6 = 18 square meters

multiply this with the height of the prism (5 meters) to get 18*5 = 90 cubic meters. I'm using the idea that,

volume of prism = (area of base face)*(height of prism)

The notation "m^3" is shorthand for "cubic meters"

We do not use the other dimensions of 9 m and 7 m.

7 0
3 years ago
The temperature is 16 degrees F in the morning and drops to -15 degrees F in the evening what is the difference between these te
Arturiano [62]
16 - (-15) = 16 + 15 = 31...difference of 31 degrees
8 0
3 years ago
Find x inscribed angles
mina [271]
The easiest variable you can solve for first is "z". Knowing that opposite angles of a quadrilateral inscribed in a circle are supplementary, subtract 93 from 180 to get z.
Z should equal 87.
The next variable we can solve for is "x". We know that inscribed angles are half the measure of their intercepting arc, so we know 93 is half of (112 + x). The equation would look like this:

93= (112 + x)/2
Multiply both sides by 2
186 = 112 + x
Subtract 112 from both sides
74 = x

Now we can apply the same method we used to find "x" to find y. Set up an equation like this:
80 = (y + x)/2
Substitute the value of x in
80 = (y + 74)/2
Multiply both sides by 2
160 = y + 74
Subtract 74 from both sides
86 = y

Hope this helps!
5 0
3 years ago
Consider the following points on cartesian plane. A (1;2) BC3; 1) and CG-3; 4) prove that Points A, B and C are collinear. ​
Arlecino [84]

Step-by-step explanation:

Collinear points have the same gradient

find the gradient(slope) between AB first

= \frac{1 - 2}{3 - 1}  \\  =  \frac{ - 1}{2}

Find the one for BC

= \frac{4 - 1}{ - 3 - 3}  \\  =  \frac{3}{ - 6}  \\  =  \frac{ - 1}{2}

Find the gradient between AC now

=  \frac{4 - 2}{ - 3 - 1}  \\  =  \frac{2}{ - 4}  \\  =  \frac{ - 1}{2}

YOUR LAST STATEMENT NOW WILL BE

POINTS A,B AND C ARE COLLINEAR SINCE THE GRADIENTS BETWEEN THEM IS THE SAME!!!

5 0
1 year ago
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