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Tcecarenko [31]
3 years ago
7

Consider the two expressions which statement is true?​

Mathematics
1 answer:
seraphim [82]3 years ago
6 0
The correct answer is: The two expressions are not equivalent because they do not always have the same value when any value is substituted for k.

Hope this helps!! :)
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Compute the permutations and combinations. 10C10 10 0 1
kozerog [31]

Answer:

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Step-by-step explanation:

i know the answere i am quite busy will answer u later

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4 years ago
PLEASE HELP OR IM gonna FAILLLLLLLL!!!!!!!!
podryga [215]

Answer:

<em>C. 1/(4^10)</em>

Step-by-step explanation:

<h2>Let's break it down: 4^-2 = 1/(4^2)</h2><h2>(1/(4^2))^5 = (1^5)/(4^2)^5 = 1/(4^10)</h2>

3 0
3 years ago
What is the area of parallelogram ABCD?<br>​
Andrej [43]

Answer:

15

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
3x^2 -5x -2=0
Kipish [7]

Answer:

Step-by-step explanation:

1. Find two numbers that add to make the coefficient of x (in this case, -5) and that multiply to make the constant term multiplied by the coefficient of x^2 (in this case, -2 x 3 = -6)

Two numbers that work are -6 and +1

-6 x +1 = -6

-6 + -1 = -5

2. Split the middle term into the two numbers that you found.

3x^2 -6x +x -2 = 0

I've put the -6 on the left side because in our next step, when we factorise, it will be easier than having the numbers the other way around.

3. Factorise the left side by taking out common factors from each pair. The pairs I'm talking about here are '3x^2 and -6x', and 'x and -2'

3x (x-2) +1 (x-2) = 0

4. You now have two numbers both being multiplied by the term x-2. We can rearrange this equation to give us two brackets being multiplied by each other.

(3x + 1) (x-2) = 0

5. According to the Null Factor Law, if two terms are multiplied together and the result is 0, then one of those terms must be 0. Make both terms equal to 0 and solve each for x.

3x + 1 = 0              x-2 = 0

3x = -1                   x = 2

x = -1/3

6. The solutions to this equation are x = 2 and x = -1/3

6 0
3 years ago
Read 2 more answers
Help no time plzzzz plz plz​
Sav [38]

Answer:

FALSE

Step-by-step explanation:

<E in ∆AED ≅ <E in ∆CEB.

Both are 90°.

Side ED ≅ Side EB

Side AD ≅ Side CB.

Thus, two sides (ED and AD) and a non-included angle (<E) of ∆AED are congruent to corresponding two sides (EB and CB) and a non-included angle (<E) of ∆CEB. Therefore, by A-S-S Congruence Theorem, both triangles are congruent to each other not by SSS.

8 0
3 years ago
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