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Tcecarenko [31]
2 years ago
7

Consider the two expressions which statement is true?​

Mathematics
1 answer:
seraphim [82]2 years ago
6 0
The correct answer is: The two expressions are not equivalent because they do not always have the same value when any value is substituted for k.

Hope this helps!! :)
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Sonia earned $2,100 at her uncle's orchard. If she worked for 70 weeks and earned the same amount of money each week, how much d
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30

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She earned 30$ a week(Brainlyest?)

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What is ten times less than 700?
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I NEED HELP!! please show all work
PtichkaEL [24]

Take the logarithm of both sides. The base of the logarithm doesn't matter.

4^{5x} = 3^{x-2}

\implies \log 4^{5x} = \log 3^{x-2}

Drop the exponents:

\implies 5x \log 4 = (x-2) \log 3

Expand the right side:

\implies 5x \log 4 = x \log 3 - 2 \log 3

Move the terms containing <em>x</em> to the left side and factor out <em>x</em> :

\implies 5x \log 4 - x \log 3 = - 2 \log 3

\implies x (5 \log 4 - \log 3) = - 2 \log 3

Solve for <em>x</em> by dividing boths ides by 5 log(4) - log(3) :

\implies \boxed{x = -\dfrac{ 2 \log 3 }{ 5 \log 4 - \log 3 }}

You can stop there, or continue simplifying the solution by using properties of logarithms:

\implies x = -\dfrac{ \log 3^2 }{ \log 4^5 - \log 3 }

\implies x = -\dfrac{ \log 9 }{ \log 1024 - \log 3 }

\implies \boxed{x = -\dfrac{ \log 9 }{ \log \frac{1024}3 }}

You can condense the solution further using the change-of-base identity,

\implies \boxed{x = -\log_{\frac{1024}3}9}

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2 years ago
Sierra drove 130 miles in 2 hours, stopped for 15
sergij07 [2.7K]

Answer:

78.26

Step-by-step explanation:

130+50= 180

.45-.15+2=2.3

180/2.3=78.26

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3 years ago
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