The number of data values between the lower quartile and the median is less than the number of data values between the upper quartile and the median.

Hope this helps!

6 0

3 years ago

X³ by a³ + a³by x³=p x³by a³- a³by ³=q eliminate x

sasho [114]

Answer:

Step-by-step explanation:

$\frac{x^3}{a^3} +\frac{a^3}{x^3} =p\\\frac{x^3}{a^3} -\frac{a^3}{x^3} =q\\adding\\2\frac{x^3}{a^3} =p+q\\\frac{x^3}{a^3} =\frac{p+q}{2} \\substitute~in~first\\\frac{p+q}{2} +\frac{2}{p+q} =p\\\frac{(p+q)^2+4}{2(p+q)} =p\\(p+q)^2+4=2p(p+q)\\p^2+q^2+2pq+4-2p^2-2pq=0\\q^2-p^2+4=0\\q^2=p^2-4$

6 0

2 years ago

A local radio station is having a contest every 12th caller receives a CD then the 20th caller receives 4 tickets to the concert

bonufazy [111]

Neither one of them will when both! Sorry

5 0

3 years ago