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kifflom [539]
3 years ago
6

Show steps using Pythagorean Theorem please

Mathematics
1 answer:
neonofarm [45]3 years ago
5 0
Same I don’t get this
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Help me with 16,17,18,and 19 please simpl
mixas84 [53]

Answer:

Ques 16)

We have to simplify the expression:

\dfrac{t^2}{t^2+3t-18}-(\dfrac{5t}{t^2+3t-18}-\dfrac{t-3}{t^2+3t-18})\\   \\=\dfrac{t^2}{t^2+3t-18}-(\dfrac{4t+3}{t^2+3t-18})\\  \\=\dfrac{t^2-4t-3}{t^2+3t+18}

Ques 17)

\dfrac{3w^2+7w-7}{w^2+8w+15}+\dfrac{2w^2-9w+4}{(2w^2+9w-5)(w^2-w-12)}\\  \\=\dfrac{3w^2+7w-7}{w^2+8w+15}+\dfrac{(2w-1)(w-4)}{(2w-1)(w+5)(w+3)(w-4)}\\\\=\dfrac{3w^2+7w-7}{(w+3)(w+5)}+\dfrac{1}{(w+3)(w+5)}\\\\=\dfrac{3w^2+7w-7+1}{(w+3)(w+5)}\\\\=\dfrac{(3w-2)(w+3)}{(w+5)(w+3)}\\\\=\dfrac{3w-2}{w+5}

Ques 18)

Let the blank space be denoted by the quantity 'x'.

\dfrac{x}{12a^2+8a}+\dfrac{15a^2}{12a^2+8a}=\dfrac{7a}{3a+2}\\ \\\dfrac{x+15a^2}{12a^2+8a}=\dfrac{7a}{3a+2}\\\\=\dfrac{x+15a^2}{4a(3a+2)}=\dfrac{7a}{3a+2}\\\\=\dfrac{x+15a^2}{4a}=7a\\\\x+15a^2=28a^2\\\\x=28a^2-15a^2\\\\x=13a^2

Ques 19)

Let the missing quantity be denoted by 'x'.

\dfrac{p^2+7p+2}{p^2+5p-14}-\dfrac{x}{p^2+5p-14}=\dfrac{p-1}{p-2}\\ \\\dfrac{p^2+7p+2-x}{p^2+5p-14}=\dfrac{p-1}{p-2}\\\\\dfrac{p^2+7p+2-x}{(p-2)(p+7)}=\dfrac{p-1}{p-2}\\\\p^2+7p+2-x=(p-1)(p+7)\\\\p^2+7p+2-x=p^2+6p-7\\\\x=p+9


7 0
3 years ago
Is 48 a perfect cube? Explain your reasoning.
Ksivusya [100]

Answer:

No

Reasoning:

If something is a perfect cube, it is able to be put under a cube root (\sqrt[3]{..}) and will result in an integer (a non-decimal number > 0, basically).

So let's calculate \sqrt[3]{48}, and see if the result is an integer.

\sqrt[3]{48} = 3.634.......

As you can see, the result is not an integer, therefore 48 is not a perfect cube.

8 0
3 years ago
I need to solve×:5×10=2
PSYCHO15rus [73]
I hope this helps you

6 0
3 years ago
2-(4p+3)=-3(p+2)-(2p+3)
statuscvo [17]
Ultimately, you want the <em>variable</em> p on one side of the equals sign, and the <em>value</em> of p on the other.

First, get rid of the parenthesis by <em>distributing.

</em>There is an invisible -1 in front of the first and last set of parenthesis, and a one times any number is the number itself, so you are essentially distributing the negative sign. 
<em>
</em>So you have:     2-4p-3 = -3p-6-2p-3
<em>
</em>Next, <em>Combine like terms.
</em>
Can you take it from there?<em>

</em>
8 0
3 years ago
Read 2 more answers
Find the solution to the system of 5x+2y=-24 x-y=5
Mashutka [201]
So to do this, we have to get rid of one of the variables by adding or subtracting the two equations together.
I will get rid of y. So, we can multiply the second equation by 2. This gives us
2x-2y=10
Now, we can add both equations
This gives us 7x=-14
Therefore, x = -2
Plug that into another equation.
-10 + 2y=-24
Therefore, y = -7

Hope this helped!! :D
4 0
4 years ago
Read 2 more answers
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