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2 years ago

Subtract these polynomials

Mathematics

2 answers:

Mamont248 [21]2 years ago

7 0

The answer should be A

SCORPION-xisa [38]2 years ago

4 0

So I couldn’t do square roots so I had to take a photo

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Saby used a probability simulator to roll a 6-sided number cube and flip a coin 100 times. The results are shown in the tables b

Degger [83]

Short Answers
P(Both) = 0.1792
Givens
The total number of roles = 100
Total number of heads = 56
Number of times rolled a four = 32 [check this for me].

Set up the probabilities.
P(H) = 56/100
P(4) = 32/100
P(H)*P(4) = P(Both)

Substitute and solve
P(Both) = 56/100 * 32/100 = 1792/10000
P(Both) = 112/625 because there are many cancellations. Or you could just express it as 0.1972

8 0

2 years ago

The volume of a sphere is a function of its radius, V=4/3(pie)(r^3). Evaluate the function for the volume of a volleyball with

Travka [436]

Volume of a volleyball (a sphere) = 4/3πr³
= 4/3π(11.4)³
= 1975.392π
= 6210 cm³ (to 3 significant figures)

The volume of a volleyball with a radius of 11.4 cm will be 6210 cm³.

5 0

3 years ago

Use the properties of logarithms to prove log, 1000 = log2 10.

Leto [7]

Given:

Consider the equation is:

$\log_81000=\log_210$

To prove:

$\log_81000=\log_210$ by using the properties of logarithms.

Solution:

We have,

$\log_81000=\log_210$

Taking left hand side (LHS), we get

$LHS=\log_81000$

$LHS=\dfrac{\log 1000}{\log 8}$ $\left[\because \log_ab=\dfrac{\log_x a}{\log_x b}\right]$

$LHS=\dfrac{\log (10)^3}{\log 2^3}$

$LHS=\dfrac{3\log 10}{3\log 2}$ $[\because \log x^n=n\log x]$

$LHS=\dfrac{\log 10}{\log 2}$

$LHS=\log_210$ $\left[\because \log_ab=\dfrac{\log_x a}{\log_x b}\right]$

$LHS=RHS$

Hence proved.

6 0

3 years ago

Need help pls<br>thank you in advance

ira [324]

Answer:

<u />

$\textsf{Mean}\:\overline{X}=\sf \dfrac{\textsf{sum of all the data values}}{\textsf{total number of data values}}$

$\implies \sf Mean\:(Nilo)=\dfrac{5+6+14+15}{4}=\dfrac{40}{4}=10$

$\implies \sf Mean\:(Lisa)=\dfrac{8+9+11+12}{4}=\dfrac{40}{4}=10$

<h3><u>Standard Deviation</u></h3>

$\displaystyle \textsf{Standard Deviation }s=\sqrt{\dfrac{\sum X^2-\dfrac{(\sum X)^2}{n}}{n-1}}$

$\begin{aligned}\displaystyle \textsf{Standard Deviation (Nilo)} & =\sqrt{\dfrac{(5^2+6^2+14^2+15^2)-\dfrac{(5+6+14+15)^2}{4}}{4-1}}\\\\& = \sqrt{\dfrac{482-\dfrac{40^2}{4}}{3}}\\\\& = \sqrt{\dfrac{82}{3}}\\\\& = 5.23\end{aligned}$

$\begin{aligned}\displaystyle \textsf{Standard Deviation (Lisa)} & =\sqrt{\dfrac{(8^2+9^2+11^2+12^2)-\dfrac{(8+9+11+12)^2}{4}}{4-1}}\\\\& = \sqrt{\dfrac{410-\dfrac{40^2}{4}}{3}}\\\\& = \sqrt{\dfrac{10}{3}}\\\\& = 1.83\end{aligned}$

<h3><u>Summary</u></h3>

Nilo has a mean score of 10 and a standard deviation of 5.23.

Lisa has a mean score of 10 and a standard deviation of 1.83.

The <u>mean</u> scores are the <u>same</u>.

Nilo's standard deviation is higher than Lisa's. Therefore, Nilo's test scores are more <u>spread out</u> that Lisa's, which means Lisa's test scores are more <u>consistent</u>.

5 0

1 year ago

Kristin spent $131 on shirts. Fancy shirts cost $28 and plain shirts cost $15. If she bought a total of 7 then how many of each

Tpy6a [65]

Hi there!!

First, Let plain shirts be x
Let fancy shirts be y
x + y = 7
15x + 28y = 131
Multiply first equation by 28 to eliminate y:
28x + 28y = 196
<span>15x + 28y = 131
</span>Subtracting the two equations:
13x = 65
<span>x = 5 </span>
Substituting x to get y:
x + y = 7
5 + y = 7
<span>y = 2 </span>
<span>Answer: 5 plain shirts and 2 fancy shirts
</span>
Hope this helps u!!
Have an amazing rest of ur day:)))

3 0

2 years ago