By using <span>De Moivre's theorem:
</span>
If we have the complex number ⇒ z = a ( cos θ + i sin θ)
∴
![\sqrt[n]{z} = \sqrt[n]{a} \ (cos \ \frac{\theta + 360K}{n} + i \ sin \ \frac{\theta +360k}{n} )](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bz%7D%20%3D%20%20%5Csqrt%5Bn%5D%7Ba%7D%20%5C%20%28cos%20%5C%20%20%5Cfrac%7B%5Ctheta%20%2B%20360K%7D%7Bn%7D%20%2B%20i%20%5C%20sin%20%5C%20%5Cfrac%7B%5Ctheta%20%2B360k%7D%7Bn%7D%20%29)
k= 0, 1 , 2, ..... , (n-1)
For The given complex number <span>⇒ z = 81(cos(3π/8) + i sin(3π/8))
</span>
Part (A) <span>
find the modulus for all of the fourth roots </span>
<span>∴ The modulus of the given complex number = l z l = 81
</span>
∴ The modulus of the fourth root =
Part (b) find the angle for each of the four roots
The angle of the given complex number =

There is four roots and the angle between each root =

The angle of the first root =

The angle of the second root =

The angle of the third root =

The angle of the fourth root =
Part (C): find all of the fourth roots of this
The first root =

The second root =

The third root =

The fourth root =
Answer: C
Step-by-step explanation: 8 (1/3) 16 (2/3) 24 (3/3)
You were right already it’s A
Answer and Step-by-step explanation:
Let
Number of chocolate chip cookies = x
Number of oatmeal brownie cookies = y
Bake chocolate chip cookies up to 20 dozen = x≤ 20
Bake oatmeal brownies up to 40 dozen= y≤40
Total cookies = x + y ≤ 50
Number of oatmeal brownie will be no more than three times the number of chocolate chip= y≤3x
From the inequality:
X + y=50
y = 3x
By putting the value of y, we get
x + 3x = 50
4x = 50
X = 12.5
By putting the value of x=12.5 in equation y = 3x, we get
Y = 3(12.5)
= 37.5
Craig should make 12.5 dozen chocolate chip and 37.5 dozen oatmeal brownies in order to make more money.
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