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3 years ago

A line passes through the points (7,6) and (8,8) What is its equation in slope intercept form?

Mathematics

1 answer:

rjkz [21]3 years ago

8 0

Answer:

Step-by-step explanation:

The slope: $m=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{8-6}{8-7}=\dfrac21=2$

y = mx + b ← slope intercept form

(8, 8) ⇒ x = 8, y = 8

so:

8 = 2·8 + b

b = - 8

The equation: y = 2x - 8

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Answer:

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Find the length of the segment with endpoints of (3, 2) and (-3, -6).

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The distance between (3, 2) and (-3, -6) is 10 units

The correct answer is B) 10

Further explanation:

Given points are:

(x1,y1) = (3,2)

(x2,y2)=(-3,-6)

The distance formula is given by:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Putting the values

$d=\sqrt{(-3-3)^2+(-6-2)^2}\\=\sqrt{(-6)^2+(-8)^2} \\=\sqrt{36+64}\\ =\sqrt{100}\\d=10$

The distance between (3, 2) and (-3, -6) is 10 units

Keywords: Magnitude, Distance

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A line passes through the points (7,6) and (8,8) What is its equation in slope intercept form?​

A line passes through the points (7,6) and (8,8) What is its equation in slope intercept form?