151° Have a great day/night!
For this case we must solve each of the functions.
We have then:
f (x) = x2 - 9, and g (x) = x - 3
h (x) = (x2 - 9) / (x - 3)
h (x) = ((x-3) (x + 3)) / (x - 3)
h (x) = x + 3
f (x) = x2 - 4x + 3, and g (x) = x - 3
h (x) = (x2 - 4x + 3) / (x - 3)
h (x) = ((x-3) (x-1)) / (x - 3)
h (x) = x-1
f (x) = x2 + 4x - 5, and g (x) = x - 1
h (x) = (x2 + 4x - 5) / (x - 1)
h (x) = ((x + 5) (x-1)) / (x - 1)
h (x) = x + 5
f (x) = x2 - 16, and g (x) = x - 4
h (x) = (x2 - 16) / (x - 4)
h (x) = ((x-4) (x + 4)) / (x - 4)
h (x) = x + 4
Answer:
1. Function
2. Function
3. Function
4. Not a Function
5. Not a Function
Step-by-step explanation:
Hope it helps:)
Answer:
Step-by-step explanation:no you should not
-9x+27=-13
-9x-27=13
-9x=18
-2=x
Answer: 
Step-by-step explanation:
1. By definition, you have if 
, then 
2. Keeping this on mind, you must follow the proccedure shown below:
- You have that:
Where:
- Substitute values into . Then, you obtain:
