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WITCHER [35]
3 years ago
11

Please answer #1 and #2

Mathematics
1 answer:
DIA [1.3K]3 years ago
6 0
1)
x^2 + (3y/2z) = 7
2x^2z + 3y = 14z
3y = 14z - 2x^2z
3y = 2z(7 - x^2)
  y = 2/3(z)(7 - x^2)

2)
(3zx^4) /(5+z) = 2y
3zx^4 = 2y(5+z)
3zx^4 = 10y + 2yz

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3. The winner of the Biggest Loser lost .952 ounce per hour. Convert this to pounds per week<br>​
Darya [45]

Answer:

....................

Step-by-step explanation:

3 0
3 years ago
Find the image of each polygon with the given vertices after a dilation centered at the origin with the given scale factor. J(2,
MAVERICK [17]

Applying a dilation centered at the origin with scale factor k has the effect of multiplying both coordinates of a point by k:

(x,y)\mapsto (kx,ky)

So, in your case, the coordinates of the points double:

J'=(4,8),\quad K'=(8,8),\quad P'=(6,4)

4 0
3 years ago
Someone plz help!!!!!! ​
aliina [53]

Answer: X = 7√2

Step-by-step explanation:

Let first Consider triangle BDC,

Cos C = adjacent/ hypothenus

Cos C = 7 / x ...... (1)

Also, let consider triangle ABC

Cos C = adjacent / hypothenus

Cos C = x / 14 ....... (2)

Since angle C is the same, equate equation 1 to 2

7/ x = x / 14

Cross multiply

X^2 = 98

Make x the subject of formula

X = sqrt (98)

X = sqrt ( 49 × 2 )

X = sqrt (49) × sqrt (2)

X = 7 sqrt(2)

X = 7√2

8 0
3 years ago
2X- 10 =30 solve for X
Kazeer [188]
2x - 10 = 30
2x = 40
x = 20
5 0
3 years ago
Read 2 more answers
1. Identify the vertex and the y-intercept of the graph of the function y=-2(x+ 2)+2.
KATRIN_1 [288]

Answer:

Please let me know if your quadratic is y=-2(x+2)^2+2.

And if so your vertex is (-2,2) and your y-intercept is (0,-6)

Step-by-step explanation:

It says vertex so I'm thinking you meant y=-2(x+2)^2+2.  Please correct me if I'm wrong.

The vertex form of a quadratic is y=a(x-h)^2+k.  It is called that because it tells you the vertex (h,k).

So if you compare the two forms you should see -h=2 while k=2.

-h=2 implies h=-2.

So the vertex is (h,k)=(-2,2).

To find the y-intercept, set x=0 and find y.

y=-2(0+2)^2+2

y=-2(2)^2+2

y=-2(4)+2

y=-8+2

y=-6

So the y-intercept is (0,-6).

7 0
3 years ago
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