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4 years ago

The probability of a biased coin landing on heads is 2/7 complete the tree diagram

Mathematics

2 answers:

mamaluj [8]4 years ago

8 0

Answer:

The numbers needed to fill each box are in the image attached

Step-by-step explanation:

The probability of the coin landing on heads is 2/7, so the probability of it landing on tails is 1 - 2/7 = 5/7

The probability of landing heads 2 times is:

P = (2/7) * (2/7) = 4/49

The probability of landing heads and then tails is:

P = (2/7) * (5/7) = 10/49

The probability of landing tails and then heads is:

P = (5/7) * (2/7) = 10/49

The probability of landing tails 2 times is:

P = (5/7) * (5/7) = 25/49

The numbers needed to fill each box are in the image attached.

Mice21 [21]4 years ago

8 0

Step-by-step:

The first flip numbers will always add up to 1 so you do

1 - 2/7= 5/7

now it gets easy...

The second flip head will be 2/7 because it is a biased dice and the second flip tail will be 5/7

This also applies for the bottom 2: 2/7 head, 5/7 tails

hope this helped :)

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Kevin and Randy Muise have a jar containing 80 coins, all of which are either quarters or nickels. The total value of the coins

SCORPION-xisa [38]

Answer:

39 quarters and 41 nickels

Step-by-step explanation:

Let the number of quarters be x and nickels be y.

Given:

Quarter is 25 cents
Nickel is 5 cents
Number of coins is 80
Total amount is $11.80 = 1180 cents

We have equations:

x + y = 80
25x + 5y = 1180

Solve the system by elimination, subtract 5 times the first equation from the second one:

25x + 5y - 5x - 5y = 1180 - 80*5
20x = 780
x = 780/20
x = 39

Find the value of y:

39 + y = 80
y = 80 - 39y = 41

Verify:

25*39 + 5*41 = 975 + 205 = 1180

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2 years ago

Which is the value of the expression (StartFraction (10 Superscript 4 Baseline) (5 squared) Over (10 cubed) (5 cubed)) cubed?

Flura [38]

Answer:

The value to the given expression is 8

Therefore $\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=8$

Step-by-step explanation:

Given expression is (StartFraction (10 Superscript 4 Baseline) (5 squared) Over (10 cubed) (5 cubed)) cubed

Given expression can be written as below

$\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3$

To find the value of the given expression:

$\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=\frac{((10^4)(5^2))^3}{((10^3)(5^3))^3}$

( By using the property ( $(\frac{a}{b})^m=\frac{a^m}{b^m}$ )

$=\frac{(10^4)^3(5^2)^3}{(10^3)^3(5^3)^3}$

( By using the property $(ab)^m=a^mb^m$ )

$=\frac{(10^{12})(5^6)}{(10^9)(5^9)}$

( By using the property $(a^m)^n=a^{mn}$ )

$=(10^{12})(5^6)(10^{-9})(5^{-9})$

( By using the property $\frac{1}{a^m}=a^{-m}$ )

$=(10^{12-9})(5^{6-9})$ (By using the property $a^m.b^n=a^{m+n}$ )

$=(10^3)(5^{-3})$

$=\frac{10^3}{5^3}$ ( By using the property $a^{-m}=\frac{1}{a^m}$ )

$=\frac{1000}{125}$

$=8$

Therefore $\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=8$

Therefore the value to the given expression is 8

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