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3 years ago

The probability of a biased coin landing on heads is 2/7 complete the tree diagram

Mathematics

2 answers:

mamaluj [8]3 years ago

8 0

Answer:

The numbers needed to fill each box are in the image attached

Step-by-step explanation:

The probability of the coin landing on heads is 2/7, so the probability of it landing on tails is 1 - 2/7 = 5/7

The probability of landing heads 2 times is:

P = (2/7) * (2/7) = 4/49

The probability of landing heads and then tails is:

P = (2/7) * (5/7) = 10/49

The probability of landing tails and then heads is:

P = (5/7) * (2/7) = 10/49

The probability of landing tails 2 times is:

P = (5/7) * (5/7) = 25/49

The numbers needed to fill each box are in the image attached.

Mice21 [21]3 years ago

8 0

The first flip numbers will always add up to 1 so you do

1 - 2/7= 5/7

now it gets easy...

The second flip head will be 2/7 because it is a biased dice and the second flip tail will be 5/7

This also applies for the bottom 2: 2/7 head, 5/7 tails

hope this helped :)

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sherman has 3 cats and 2 dogs he wants to buy sa toy for each of his pets sherman has 22$ to spend on toys how much can he spend

son4ous [18]

Total pets = 3+2 =5.

Total money = $22

Money for each pet would be:

22/5 in fraction .

$4.40 in dollars & cents.

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3 years ago

Given a sample space, and events A and B, where P(A)= 0.5 and P(B)=0.5. Which of the following values for P(A and B) are not pos

user100 [1]

Option a, option b, option c, option d are not possible values for P(A ∩ B)

Solution:

Given A and B are independent events.

P(A) = 0.5 and P(B) = 0.5

To find which of the following values for P(A and B) are not possible.

P(A and B) = P(A ∩ B)

P(A ∩ B) = P(A) × P(B)

= 0.5 × 0.5

P(A ∩ B) = 0.25

Option a: All are possible.

All answers are not possible for two independent events.

Option b: 0.35

We found that P(A and B) is 0.25.

So, 0.35 is not possible value.

Option c: 0.5

We found that P(A and B) is 0.25.

So, 0.5 is not possible value.

Option d: 0

We found that P(A and B) is 0.25.

So, 0 is not possible value.

Option e: 0.25

We found that P(A and B) is 0.25.

So, 0.25 is the possible value.

Hence, 0.35, 0.5, 0 are not possible values.

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3 years ago

-20÷5(-3)+4(-2)(-1)-4²<br>step by step please and thank you!

disa [49]

$\huge \boxed{\mathbb{QUESTION} \downarrow}$

$\large \tt \: -20 \div 5(-3)+4(-2)(-1)-4 ^ { 2 }$

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$\tt \: -20 \div 5(-3)+4(-2)(-1)-4 ^ { 2 }$

Divide -20 by 5 to get -4.

$\tt \: -4\left(-3\right)+4\left(-2\right)\left(-1\right)-4^{2}$

Multiply -4 and -3 to get 12.

$\tt \: 12+4\left(-2\right)\left(-1\right)-4^{2}$

Multiply 4 and -2 to get -8.

$\tt \: 12-8\left(-1\right)-4^{2}$

Multiply -8 and -1 to get 8.

$\tt \: 12+8-4^{2}$

Add 12 and 8 to get 20.

$\tt \: 20-4^{2}$

Calculate 4 to the power of 2 and get 16.

$\tt \: 20-16$

Subtract 16 from 20 to get 4.

$= \boxed{\boxed{ \bf 4}}$

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3 years ago

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just olya [345]

Answer:

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Step-by-step explanation:

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Answer:

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