Question

-20÷5(-3)+4(-2)(-1)-4²step by step please and thank you!​

Answer 1

$\huge \boxed{\mathbb{QUESTION} \downarrow}$

$\large \tt \: -20 \div 5(-3)+4(-2)(-1)-4 ^ { 2 }$

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$\tt \: -20 \div 5(-3)+4(-2)(-1)-4 ^ { 2 }$

Divide -20 by 5 to get -4.

$\tt \: -4\left(-3\right)+4\left(-2\right)\left(-1\right)-4^{2}$

Multiply -4 and -3 to get 12.

$\tt \: 12+4\left(-2\right)\left(-1\right)-4^{2}$

Multiply 4 and -2 to get -8.

$\tt \: 12-8\left(-1\right)-4^{2}$

Multiply -8 and -1 to get 8.

$\tt \: 12+8-4^{2}$

Add 12 and 8 to get 20.

$\tt \: 20-4^{2}$

Calculate 4 to the power of 2 and get 16.

$\tt \: 20-16$

Subtract 16 from 20 to get 4.

$= \boxed{\boxed{ \bf 4}}$