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Elis [28]
3 years ago
9

Over the last three evenings Lucy received a total of 122 phone calls at the call center. The first evening she received 10 fewe

r calls than the third evening. The second evening she received 4 times as many calls as the third evening. How many phone calls did she receive each evening?
Mathematics
1 answer:
Zanzabum3 years ago
4 0

Answer:

<em>SOLUTION: Over the last three evenings, Heather received a total of 109 phone calls at the call center. The third evening, she received 4 times as many calls as the second evening</em>

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lord [1]
2 or 3 I would say... hope that helps : ) 









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Which expression gives the solutions -5x+2x^2=-6x?(1pt)
irina [24]
This is the concept of algebra, the solution of the given expression will be given as follows;
-5x+2x²=-6x
adding 5x on both sides we get
5x-5x+2x²=-6x+5x
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divide both sides by 2
(2x²)/2=-x/2
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divide both sides by x
(x²)/x=-x/(2x)
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the answer is x=-1/2
8 0
3 years ago
The following data show the weight, in ounces, of 10 different bags of candy:
LuckyWell [14K]
B) is correct; on average, each bag of candy has a weight that is 2.6 oz different than the mean weight of 5 oz.

To find the mean absolute deviation, we first find the mean.  Find the sum of the data points and divide by the number of data points (without the outlier, 21, in it):
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Now we find the difference between each data point and the mean, take its absolute value, and find their sum:
|10-5|+|3-5|+|7-5|+|3-5|+|4-5|+|6-5|+|10-5|+|1-5|+|2-5|+|4-5| =
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We now divide this by the number of data points:
26/10 = 2.6

This is a measure of how much each bag of candy varies from the mean.
4 0
3 years ago
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Find the distance between the points of intersection of the graphs of the functions.
Viefleur [7K]

Answer:

Find the value of x and y in coordinate form, that'll be the point of intersection.

Question 1

{ \rm{y =  {x}^{2} - 3x + 4 }} \\ { \boxed{ \tt{but \: y = x + 1 \: }}} \\  \\ { \rm{(x + 1) =  {x}^{2} - 3x + 4 }} \\  \\ { \rm{ {x}^{2} - 4x + 3 = 0 }} \\  \\ { \rm{(x - 3)(x - 1) = 0}} \\  \\ { \boxed{ \rm{x_{1} = 3 \:  \: and \:  \: x _{2}  = 1}}} \\  \\ { \boxed{ \tt{remember \: y = x + 1}}} \\  \\ { \rm{y _{1} = 4 \:  \: and \:  \: y _{2}  = 2 }}

Therefore, points of intersection are two

Answer: <u> </u><u>(</u><u>3</u><u>,</u><u> </u><u>4</u><u>)</u><u> </u><u>and</u><u> </u><u>(</u><u>1</u><u>,</u><u> </u><u>2</u><u>)</u>

Question 2:

Following the steps as in question 1

{ \rm{y =  {x}^{2}  - 4}} \\  \\{ \rm{2x - 4 =  {x}^{2}  - 4}} \\  \\ { \rm{ {x}^{2} = 2x }} \\  \\ { \boxed{ \rm{x = 2}}} \\ { \tt{remember : \: y = 2x - 4 }} \\ { \boxed{ \rm{y = 0}}}

Answer: <u>(2, 0)</u>

7 0
3 years ago
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The length of a rectangle picture frame is 2 centimeters more than twice it’s width. If the area of the frame is 364 square cent
sergeinik [125]

Answer:

Length:28 cm

Width: 13 cm

Step-by-step explanation:

Let

x ---> the length of a rectangle picture frame

y ---> the width of a rectangle picture frame

we know that

The area of a rectangle picture frame is equal to

A=xy

we have

A=364\ cm^2

so

364=xy ----> equation A

The length of a rectangle picture frame is 2 centimeters more than twice it’s width

so

x=2y+2 ---> equation B

Solve the system by graphing

Remember that the solution is the intersection point both graphs

The solution is the point (28,13)

see the attached figure

therefore

Length:28 cm

Width: 13 cm

5 0
3 years ago
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