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3 years ago

What is the fornula for find arithemetic ewuation

Mathematics

1 answer:

-Dominant- [34]3 years ago

3 0

Answer:

a_{n} = a_{1} + (n-1)d

a_n = the nᵗʰ term in the sequence

a_1 = the first term in the sequence

d = the common difference between terms

The general term of an arithmetic sequence can be written in terms of its first term a1, common difference d, and index n as follows: an=a1+(n−1)d. ... The nth partial sum of an arithmetic sequence can be calculated using the first and last terms as follows: Sn=n(a1+an)2.

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A recipe for salad dressing calls for 3 tablespoons of oil for every 2 tablespoons of vinegar. The line represents the relations

pochemuha

Answer:

3:2, 3 to 2

Step-by-step explanation:

4 0

3 years ago

I need help with this. Im so confused

vekshin1

2. .8333333 repeated 3x1\3 is 1 the 1x5\6 is .83
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3 years ago

-2/5x+6=8 can you help me

ale4655 [162]

If you would like to solve the equation - 2/5 * x + 6 = 8, you can do this using the following steps:

- 2/5 * x + 6 = 8
- 2/5 * x = 8 - 6
- 2/5 * x = 2 /*(-5/2)
x = 2 * (- 5/2)
x = - 5

The correct result would be -5.

7 0

3 years ago

Read 2 more answers

A researcher claims that the variation in the salaries of elementary school teachers is greater than the variation in the salari

guajiro [1.7K]

Answer:

The null hypothesis is $H_o : \sigma^2_1 = \sigma^2 _2$

The alternative hypothesis is $H_a : \sigma_1 ^2 > \sigma^2_2$

$F_{critical} = 1.8608$

$F = 2.9085$

The decision rule is

Reject the null hypothesis

There is sufficient evidence to support the researchers claim

Step-by-step explanation:

From the question we are told that

The first sample size is $n_1 = 30$

The sample variance for elementary school is $s^2_1 = 8324$

The second sample size is $n_2 = 30$

The sample variance for the secondary school is $s^2_2 = 2862$

The significance level is $\alpha = 0.05$

The null hypothesis is $H_o : \sigma^2_1 = \sigma^2 _2$

The alternative hypothesis is $H_a : \sigma_1 ^2 > \sigma^2_2$

Generally from the F statistics table the critical value of $\alpha = 0.05$ at first and second degree of freedom $df_1 = n_1 - 1 = 30 - 1 = 29$ and $df_2 = n_2 - 1 = 30 - 1 = 29$ is