9514 1404 393
Answer:
2√30 ∠-120°
Step-by-step explanation:
The modulus is ...
√((-√30)² +(-3√10)²) = √(30 +90) = √120 = 2√30
The argument is ...
arctan(-3√10/-√30) = arctan(√3) = -120° . . . . a 3rd-quadrant angle
The polar form of the number can be written as ...
(2√30)∠-120°
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<em>Additional comments</em>
Any of a number of other formats can be used, including ...
(2√30)cis(-120°)
(2√30; -120°)
(2√30; -2π/3)
2√30·e^(i4π/3)
Of course, the angle -120° (-2π/3 radians) is the same as 240° (4π/3 radians).
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At least one app I use differentiates between (x, y) and (r; θ) by the use of a semicolon to separate the modulus and argument of polar form coordinates. I find that useful, as a pair of numbers (10.95, 4.19) by itself does not convey the fact that it represents polar coordinates. As you may have guessed, my personal preference is for the notation 10.95∠4.19. (The lack of a ° symbol indicates the angle is in radians.)
Answer:
3=111
Step-by-step explanation:
Answer:
y approaches negative infinty
Answer:
4y = x - 17
Step-by-step explanation:
First off, in the equation given : 2x + 5y = 6 , make y the subject of the formula which will give y = 
+ 
which make the gradient, m, the coefficient of x = 
. Since the line we're looking for is parallel to the one we were given, their respective gradients would be the same. (If they were perpendicular, the gradient of the new line would be a negative inverse of the given line)
Then you proceed to use the one-point formula : y - y₀ = m(x - x₀), where y₀ = 3 and x₀ = 5 from the point it goes through (5, 3)
y - 3 = 
(x - 5); y - 3 = 
- 
; y = - +3
y = - 
; y = 
; 4y = x - 17
Answer:
mack and hack was wearing jacks hat
Step-by-step explanation:
