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Alex Ar [27]
3 years ago
15

Yong is measuring two pyramids whose bases are rectangles.

Mathematics
1 answer:
ElenaW [278]3 years ago
7 0

Answer:

Answer is 7/2 cm

Step-by-step explanation:

1. Set a ratio

7=\frac{3V}{l*w}:h=\frac{3V}{l*2w}

2. Move 2w from denominator to LHS (Left hand side)\frac{7}{2}w=\frac{3V}{l}

\frac{7}{2w}=\frac{3V}{l}

3. The four options are 7/4, 7/2, 14 or 28 cm

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Step-by-step explanation:

a+(a+60)=760

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a+60=student tickets

a+a+60=2a+60

2a+60=760

-60 -60

2a=700

÷2. ÷2

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3 years ago
Find the distance between the two points (2,5) and (6,-1)
Reptile [31]

Answer:

= \sqrt{52} units

Step-by-step explanation:

x₁ = 2 ; y₁ = 5

x₂ = 6 ; y₂ = -1

D = \sqrt{(x₂ - x₁)² + (y₂ - y₁)²}

   =\sqrt{(6 - 2)² + (-1 -5)²}

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D = \sqrt{52} units

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3 years ago
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Answer:

B)5/12 Hope It Help

Step-by-step explanation:

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2 years ago
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Suppose that 3 balls will be randomly put into 3 buckets, with each ball being equally likely to be put into each of the buckets
Yuliya22 [10]

Answer:

\frac{1}{27}

Step-by-step explanation:

Since there are a total of three buckets and only one can be chosen at a time, this would mean that the probability of a ball being placed in a bucket is 1/3. Since each ball has the same probability of being placed into any bucket regardless of the where the previous ball landed, it means that each ball has the same 1/3 probability of a bucket. In order to find the probability that all three land in the same bucket, we need to multiply this probability together for each one of the balls like so...

\frac{1}{3} * \frac{1}{3} * \frac{1}{3}  = \frac{1}{27}

Finally, we see that the probability of all three balls landing in the same bucket is \frac{1}{27}

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3 years ago
10 POINTS !! :( ANSWER BOTH PLS !! DUE BEFORE 11:59 PM
fenix001 [56]

Answer:

Easy,

1) To find the area you need to multiply. Therefore 10 x 4 = 40 square centimeters.

2) 20, why? A calculator online for area of a triangle, it really helps! :) just look up triangle area in the future.

Step-by-step explanation:

8 0
3 years ago
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