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skelet666 [1.2K]
3 years ago
8

Find the slope of the line 6x + 5y = -5

Mathematics
1 answer:
Tanya [424]3 years ago
5 0

Answer:

Using the y=mx+b formula: -6/5

Step-by-step explanation:

6x + 5y = -5

5y = -6x -5

y = -6/5x -1

The slope would be -6/5, meaning the line would travel 5 to the right and 6 down, starting from the coordinate 0, -1.

Hope I helped.

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2)we express the total cost in cents:
$1=100 cents

$45.2=$45.2 * (100 cents /$1)=4520 cents.

3)we divide 4520 cents  among the number of pupils

Each student will pay=4520 cents / 26 =173.84... cents≈174 cents.

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3 years ago
Create a list of steps, in order, that will solve the following equation. 3(x+1)^2=108
lutik1710 [3]
I hope this helps :)

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4 years ago
A rectangular box has length 20cm, width 6cm and height 4cm. find how many cubes of size 2cm that will fit into the box.​
Papessa [141]

<u>Answer:</u>

\boxed{\pink{\sf The \ number \ of \ cubes \ that \ can \ be \ fitted \ is 60 .}}

<u>Step-by-step explanation:</u>

Given dimensions of the box = 20cm × 6cm × 4cm .

Dimension of the cube = 2cm × 2cm × 2cm .

Therefore the number of cubes that can be fitted into the box will be equal to the Volume of box divided by the Volume of the cube. So ,

\boxed{\red{\bf \implies No. \ of \ cubes \ = \dfrac{Volume \ of \ box}{Volume \ of \ cube }}}

\bf \implies n_{cubes} = \dfrac{20cm \times  6cm \times 4cm .}{2cm  \times 2cm  \times 2cm } \\\\\bf\implies n_{cubes}  = 10 \ times 3cm \times 2cm \\\\\implies \boxed{\bf n_{cubes}= 60 }

<h3><u>Hence</u><u> the</u><u> </u><u>number</u><u> </u><u>of</u><u> </u><u>cubes</u><u> </u><u>that</u><u> </u><u>can</u><u> </u><u>be</u><u> </u><u>fitted</u><u> </u><u>in</u><u> the</u><u> </u><u>box </u><u>is</u><u> </u><u>6</u><u>0</u><u> </u><u>.</u></h3>

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Doss [256]

Answer:

C. Semiannual

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A class is made up of 8 boys and 8 girls
rodikova [14]
Hello,

The answer is "8:8 or 1".

Reason:

There are 8 boys and 8 girls therefore the ratio would be...

8:8

8:8=1

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit
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