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frozen [14]
3 years ago
6

How to answer this? x+1/x+7 is less than or equal to 0

Mathematics
1 answer:
spin [16.1K]3 years ago
8 0
Solve the rational inequality by combining expressions and isolating the variable x
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Nonrigid transformation changes the size but not the shape.
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The following data table represents the total cost of a monthly cell phone bill as a function of the number of minutes that the
Mnenie [13.5K]

Answer:

$310.00 is the monthly payment if the phone was used for a total of 2,500 minutes.

Step-by-step explanation:

Since 500 minutes gets $62.00, we can multiply both to get 2,500 minutes, and $310.00.

<h2><u>Hope This Helped!</u></h2>
5 0
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NO LINKSSS!!!! PLSS HELPPPP QUICKKK PLEASEEE QUICK I WOULD PUT YOU BRAINIEST IF CORRECT PLSSS HELPPP Find the point-slope equati
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Step-by-step explanation:

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y-9 = 3/2(x-6)

y-9 = 3/2x - 9

y = 3/2x

4 0
3 years ago
Which fraction can be replaced with 0 when estimating with fractions?
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Answer:

None

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Detmermine the best method to solve the following equation, then solve the equation. (3x-5)^2=-125
liq [111]

For the given equation;

(3x-5)^2=-125

We shall begin by expanding the parenthesis on the left side, after which we would combine all terms on and move all of them to the left side, which shall yield a quadratic equation. Then we shall solve.

Let us begin by expanding the parenthesis;

\begin{gathered} (3x-5)^2\Rightarrow(3x-5)(3x-5) \\ (3x-5)(3x-5)=9x^2-15x-15x+25 \\ (3x-5)^2=9x^2-30x+25 \end{gathered}

Now that we have expanded the left side of the equation, we would have;

\begin{gathered} 9x^2-30x+25=-125 \\ \text{Add 125 to both sides and we'll have;} \\ 9x^2-30x+25+125=-125+125 \\ 9x^2-30x+150=0 \end{gathered}

We shall now solve the resulting quadratic equation using the quadratic formula as follows;

\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{Where;} \\ a=9,b=-30,c=150 \\ x=\frac{-(-30)\pm\sqrt[]{(-30)^2-4(9)(150)}}{2(9)} \\ x=\frac{30\pm\sqrt[]{900-5400}}{18} \\ x=\frac{30\pm\sqrt[]{-4500}}{18} \\ x=\frac{30\pm\sqrt[]{-900\times5}}{18} \\ x=\frac{30\pm\sqrt[]{-900}\times\sqrt[]{5}}{18} \\ x=\frac{30\pm30i\sqrt[]{5}}{18} \\ \text{Therefore;} \\ x=\frac{30+30i\sqrt[]{5}}{18},x=\frac{30-30i\sqrt[]{5}}{18} \\ \text{Divide all through by 6, and we'll have;} \\ x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3} \end{gathered}

ANSWER:

x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3}

3 0
1 year ago
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