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mezya [45]
3 years ago
10

What number do you multiply 5/3 by to get the product of 1

Mathematics
1 answer:
Usimov [2.4K]3 years ago
5 0

Answer:

3/5

Step-by-step explanation:

Any number multiplied by it's reciprocal will get you the product of 1

(Can you mark me Brainliest)

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I met this hella weird cryptic dude who interviewed me and gave me this puzzle. Solve it within 12 hours and ill let you know wh
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no cheating thanks <3

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2 years ago
Verify that -5, 1/2, and 3/4 are the zeroes of the cubic polynomial 4x^3+20x^2+2x-3. Also verify the relationship between the ze
Finger [1]

Solution:

we have been asked to verify that -5, 1/2, and 3/4 are the zeroes of the cubic polynomial 4x^3+20x^2+2x-3

To verify that whether the given values are zeros or not we will substitute the values in the given Polynomial, if it will returns zero, it mean that value is Zero of the polynomial. But if it return any thing other than zeros it mean that value is not the zero of the polynomial.

Let f(x)=4x^3+20x^2+2x-3\\\\\text{when x=-5}\\\\f(-5)=4(-5)^3+20(-5)^2+2(-5)-3=-13\\\\\text{when x=}\frac{1}{2}\\

f( \frac{1}{2} ) = 4 ( \frac{1}{2} )^3+20(\frac{1}{2})^2+2(\frac{1}{2})-3=\frac{7}{2}\\\\

\text{when x=}\frac{3}{4}\\\\

f( \frac{3}{4} ) = 4 ( \frac{3}{4} )^3+20(\frac{3}{4})^2+2(\frac{3}{4})-3=\frac{183}{16}\\

Hence -5, 1/2, and 3/4 are not the zeroes of the given Polynomial.

Since sum of roots=\frac{-b}{a}= \frac{-20}{4}=-5\\

But -5+\frac{1}{2}+\frac{3}{4}=  \frac{-15}{4}\neq-5

Hence we do not find any relation between the coefficients and zeros.

Anyway if the given values doesn't represents the zeros then those given values will not have any relation with the coefficients of the p[polynomial.

6 0
2 years ago
1 Calculate:
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(a)=940
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3 years ago
The polygons in each pair are similar.Find the missing side length
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Read 2 more answers
Solve for x<br><br> 3(ax + 9) = -4 (-2 - 10x)
ivolga24 [154]

Answer:

19

-----   =   x

40-3a

Step-by-step explanation:

3(ax + 9) = -4 (-2 - 10x)

Distribute

3ax +27 = 8+40x

Subtract 3ax from each side

3ax-3ax +27 = 8+40x-3ax

27 = = 8+40x-3ax

Subtract 8 from each side

27-8 = 8-8+40x-3ax

19 = 40x-3ax

Factor an x on the right side

19 = x(40-3a)

Divide each side by 40-3a

19/(40-3a) = x(40-3a)/(40-3a)

19

-----   =   x

40-3a

8 0
2 years ago
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