Answer:
The approximate length of the diagonal walkway is 21.21 meters
Step-by-step explanation:
we know that
Applying the Pythagorean Theorem in the square park, find out the the approximate length of the diagonal walkway
so
where
c is the diagonal of the square
a and b are the length sides of the square
we have
substitute
therefore
The approximate length of the diagonal walkway is 21.21 meters
I would like to ask you to go to the vet, or attempt to, as this might be a worm in the eye. The same thing happened to my dog.
Alright, so we have 1.3/0.0338. Since it's easier (in my opinion) to work with whole numbers, we can multiply the fraction by 10000/10000 to get 13000/338. With a bit of guess and check, we can see that
338*30=338*3*10
1 2 (what I carry is at the top)
338
x3
____
1114
Multiplying that by 10, I get 11140, which isn't enough. Trying 338*40, which is 338*4*10, we can add 338 to 338*3 to get 338*4 to get
2
1114
+338
____
1462
Multiplying that by 10, we get 14620, which is more than 13000 - something we don't want. Repeating this for 338*35 (which is 338*3.5*10, and 3.5 is 3*338+338/2)=11830 and which isn't enough, we then move on to something between 35 and 40 (the number doesn't matter), say 39. 338*39=338*3.9*10, and 338*3.9 is 338*3+338*9/10, and
338*39 results to 13182, which is more than 13000 , but only by a tiny bit, so we can try 38 using the same method, getting 12844, which is smaller, so we know it's between 38 and 39. Finding the difference between 13000 and 12844, we get 13000-12844=156 and the answer is therefore 38+156/338
Answer:
[12, 15]
Step-by-step explanation:
{6x + 5y = 147
{8x + 4y = 156
-¾[8x + 4y = 156]
{6x + 5y = 147
{-6x - 3y = -117 ← New Equation
________________
2y = 30
___ ___
2 2
y = 15 [Plug this back into both equations to get the x-coordinate of 12]; 12 = x
So, using the Elimination Method, what I did here was took the bottom equation and multiplied it by -¾, turning 8x to -6x, canceling out all <em>x-terms</em><em>.</em><em> </em>It does not matter which variable you choose to eliminate, as long as you know what you are doing.
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The time William would arrive in town B IS 1 : 47 pm.
<h3>What time will William arrive in town B?</h3>
The first step is to determine the distance and the time of Dennis's travel.
Time = 14 hours (2 pm + 12) - 10 hours = 4 hours
Distance = time x average speed
4 x 52 = 208 miles
The second step is to determine the time of William's travel:
Distance / average speed = time
208 / 40 = 5.20 = 5 hours 12 minutes
Time William left for the trip = 10 am - 1 hour 25 minutes = 8 :35am
Time he would reach town B = 8 : 35am + 5 hours 12 minutes = 13 hours 47 minutes = 1 : 47 pm
To learn more about average speed, please check: brainly.com/question/21734785
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