Answer:
a) see below
b) 40x20 meters
Step-by-step explanation:
Write down what you know:
- The area of the enclosure is length*width, so
- The length of the fencing is 80 meters, so
Now we have to combine these two equations above, and get rid of y in the process.
First rewrite the second as:
Then substitute for y in the first:
b) To maximize A, find the zero of the first derivative:
So y = (80-40)/2 = 20 meters.
13x - 6y = 22
x - y = 6
6(x-y) = 6*6
6x - 6y = 36
subtract both the equations
13x - 6x -6y + 6y = -14
7x = -14
x = -2
13*-2 -6y=22
-26 -6y=22
-6y = 48
y = -8
answer: x = -2
y = -8
Answer:
considering angle a to 40
b and c.....= 50 both
Suggestion: Please show the problem for the questions, or I'm afraid I can't help!
Y=4^x-3 translated down 3 units
y=4^x+3 translated up 3 units
y=-4^x-3 translated down 3 units and vertical reflection
y=-4^x+3 translated up 3 units and verticals reflection
