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Lapatulllka [165]
3 years ago
10

Which of the lines below is parallel to a line with a slope of 3 and a y-intercept at (0, 3)?

Mathematics
1 answer:
Dmitrij [34]3 years ago
6 0

Answer:

\displaystyle line\:HJ

Step-by-step explanation:

\displaystyle y = 3x + 3

The descryption gives you the above <em>Slope-Intercept Equation</em>. Parallel equations have SIMILAR <em>RATE</em><em> </em><em>OF</em><em> </em><em>CHANGES</em><em> </em>[<em>SLOPES</em>], therefore \displaystyle 3 remains as is, and perfourming \displaystyle \frac{rise}{run}, will give you that answer.

I am joyous to assist you at any time.

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Sally had $26. Then she earned some more money doing chores.
stich3 [128]

Answer:

$9

Step-by-step explanation:

Sally started with $26 and ended with $35 meaning she earned money

If she began with a lower number than she started with, you have to subtract the greater number by the lower to find the difference

35-26 = 9

THEREFORE she made $9 doing chores

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3 years ago
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1 /4 of a number decreased by 5 is 19 what is the number
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Step-by-step explanation:

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Will give brainliest! Need help asap!
denis23 [38]

Answer:  B.     u+2b=28

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Which family of function does the graph on the right belongs to?
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If an object is projected upward with an initial velocity of 123 ft per​ sec, its height h after t seconds is h=−16t2+123t. Find
Alinara [238K]

Answer:

Height after 5 seconds is <em>215 ft</em>

Step-by-step explanation:

Given that:

The initial velocity of object which is projected upwards is 123 ft/sec.

Height of the object, <em>h</em> after time <em>t </em> in seconds,  is given as:

h=-16t^2+123t

Here, <em>t </em>will always be positive, so 123t and 16t^2 will also be positive.

But coefficient of 16t^2 is negative, that means something is subtracted from the positive term 123t.

To find:

Height of object after 5 seconds.

Solution:

Given that t=5 seconds.

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