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Lapatulllka [165]
3 years ago
10

Which of the lines below is parallel to a line with a slope of 3 and a y-intercept at (0, 3)?

Mathematics
1 answer:
Dmitrij [34]3 years ago
6 0

Answer:

\displaystyle line\:HJ

Step-by-step explanation:

\displaystyle y = 3x + 3

The descryption gives you the above <em>Slope-Intercept Equation</em>. Parallel equations have SIMILAR <em>RATE</em><em> </em><em>OF</em><em> </em><em>CHANGES</em><em> </em>[<em>SLOPES</em>], therefore \displaystyle 3 remains as is, and perfourming \displaystyle \frac{rise}{run}, will give you that answer.

I am joyous to assist you at any time.

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Is the number -<img src="https://tex.z-dn.net/?f=%5Cfrac%7B13%7D%7B1%7D" id="TexFormula1" title="\frac{13}{1}" alt="\frac{13}{1}
Alenkasestr [34]

Answer:

13/1 = 13 is the only number integer that divides into it, but all numbers that can be fractions are rational numbers, whether decimal or prime they all can be rational.

Step-by-step explanation:

4 0
3 years ago
I need help with these two problems please
Debora [2.8K]

Problem 2

Plot point L anywhere that isn't on segment JK. Draw a line through point L. I find it helps to make the lines parallel.

Next, use a compass to measure the width of segment JK. Keeping this same width, transfer the nonpencil end of the compass to point L. Draw an arc that crosses the line through L.

Mark this intersection point M. Lastly, use a pen or marker to form segment LM and erase everything else of that line.

======================================================

Problem 3

The ideas of the previous problem will be used here. We copied segment JK to form congruent segment LM. So JK = LM.

The same steps will be used to form segment GN where GN = EF. In other words, segment GN is a perfect copy of segment EF.

If you repeat these steps again, you'll get another segment of the same length. This segment goes from point N to point H. So NH = GN = EF

Then we can say,

GH = GN + NH

GH = EF + EF

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\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the concept of expo functions.

f(x) = -8(2)^x - 12 ,

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