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valkas [14]
3 years ago
15

What is the relative formula mass of butane?​

Chemistry
1 answer:
skad [1K]3 years ago
7 0

Answer:

The molecular formula of butane is C4H10. Calculate its molar mass.58.1 g/mole 14. is answer.

Explanation:

I hope it's helpful!

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Answer:

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Explanation:

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odium carbonate (Na2CO3Na2CO3) is used to neutralize the sulfuric acid spill. How many kilograms of sodium carbonate must be add
Arte-miy333 [17]

Answer : The mass of sodium carbonate added to neutralize must be, 6.54\times 10^3kg

Explanation :

First we have to calculate the moles of H_2SO_4.

\text{Moles of }H_2SO_4=\frac{\text{Mass of }H_2SO_4}{\text{Molar mass of }H_2SO_4}

Given:

Molar mass of H_2SO_4 = 98 g/mole

Mass of H_2SO_4 = 6.05\times 10^3kg=6.05\times 10^6g

Conversion used : (1 kg = 1000 g)

Now put all the given values in the above expression, we get:

\text{Moles of }H_2SO_4=\frac{6.05\times 10^6g}{98g/mol}=6.17\times 10^4mol

The moles of H_2SO_4 is, 6.17\times 10^4mol

Now we have to calculate the moles of Na_2CO_3

The balanced neutralization reaction is:

Na_2CO_3+H_2SO_4\rightarrow Na_2SO_4+H_2CO_3

From the balanced chemical reaction we conclude that,

As, 1 mole of H_2SO_4 neutralizes 1 mole of Na_2CO_3

So, 6.17\times 10^4mol of H_2SO_4 neutralizes

Now we have to calculate the mass of Na_2CO_3

\text{ Mass of }Na_2CO_3=\text{ Moles of }Na_2CO_3\times \text{ Molar mass of }Na_2CO_3

Molar mass of Na_2CO_3 = 106 g/mole

\text{ Mass of }Na_2CO_3=(6.17\times 10^4mol)\times (106g/mole)=6.54\times 10^6g=6.54\times 10^3kg

Thus, the mass of sodium carbonate added to neutralize must be, 6.54\times 10^3kg

3 0
4 years ago
Identify 10 different Element's that Exhibit Isotopy.?​
k0ka [10]
Hey what to say I Love is your day going camping today so you don’t wanna the time
6 0
3 years ago
If 0.507J of heat leads to a 0.007 degree C change in water, what mass is present?
Ivanshal [37]

Answer:

17.3 g

Explanation:

<u>Given the following data;</u>

  • Quantity of heat, Q = 0.507 J
  • Temperature = 0.007°C
  • Specific heat capacity of water = 4.2 J/g°C

Mathematically, Heat capacity is given by the formula;

Q = MCT

Where;

  • Q represents the heat capacity or quantity of heat.
  • M represents the mass of an object.
  • C represents the specific heat capacity of water.
  • T represents the temperature.

Making "M" the subject of formula, we have;

Mass, \ m = \frac {Q}{CT}

Substituting the values into the formula, we have;

Mass, \ m = \frac {0.507}{0.007*4.2}

Mass, \ m = \frac {0.507}{0.0294}

<em>Mass, m = 17.3 grams</em>

3 0
3 years ago
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