Question

If 0.507J of heat leads to a 0.007 degree C change in water, what mass is present?

Answer 1

Answer:

17.3 g

Explanation:

Given the following data;

• Quantity of heat, Q = 0.507 J
• Temperature = 0.007°C
• Specific heat capacity of water = 4.2 J/g°C

Mathematically, Heat capacity is given by the formula;

$Q = MCT$

Where;

• Q represents the heat capacity or quantity of heat.
• M represents the mass of an object.
• C represents the specific heat capacity of water.
• T represents the temperature.

Making "M" the subject of formula, we have;

$Mass, \ m = \frac {Q}{CT}$

Substituting the values into the formula, we have;

$Mass, \ m = \frac {0.507}{0.007*4.2}$

$Mass, \ m = \frac {0.507}{0.0294}$

Mass, m = 17.3 grams