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Olin [163]
2 years ago
8

Need help plzzzzzzzzzzxx

Mathematics
1 answer:
densk [106]2 years ago
8 0

9514 1404 393

Answer:

  (a)  15/17

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the cosine relation:

  Cos = Adjacent/Hypotenuse

  cos(P) = PQ/PR

  cos(P) = 15/17

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|−12| = 12 True or False please help!!!!!
Alexandra [31]

Answer:

yes

Step-by-step explanation:

|-12| = |12| they always equal to 12

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Answer:

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Step-by-step explanation:

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Translate each verbal phrase into an algebraic expression or equation.
mario62 [17]

Answer:

13) 7 + x/2 = 10

14)  2x - 5 = 7

15) 4x - 1 = 11

16) 6x - 6 = 12

17) x/3 + 10 = 12

18) 2x + 7 = 1

19) 9 + x/7 = 11

20) 8(n - 3)

Step-by-step explanation:

The quotient of x and 2 = x ÷ 2 = x/2

The product is the result of multiplying two or more other numbers

The sum is the result of adding two or more numbers

The difference is the result of subtracting one number from another

13) 7 + x/2 = 10

14)  2x - 5 = 7

15) 4x - 1 = 11

16) 6x - 6 = 12

17) x/3 + 10 = 12

18) 2x + 7 = 1

19) 9 + x/7 = 11

20) 8(n - 3)

7 0
2 years ago
Kyle leaves a 15% tip for lunch bill of $12 what amount tip does Kyle leave
Aleonysh [2.5K]
Kyle leaves 1.80 because you have to do 0.15*12
8 0
3 years ago
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Suppose that S is the set of successful students in a classroom, and that F stands for the set of freshmen students in that clas
lora16 [44]

Answer:

b) 24

Step-by-step explanation:

We solve building the Venn's diagram of these sets.

We have that n(S) is the number of succesful students in a classroom.

n(F) is the number of freshmen student in that classroom.

We have that:

n(S) = n(s) + n(S \cap F)

In which n(s) are those who are succeful but not freshmen and n(S \cap F) are those who are succesful and freshmen.

By the same logic, we also have that:

n(F) = n(f) + n(S \cap F)

The union is:

n(S \cup F) = n(s) + n(f) + n(S \cap F)

In which

n(S \cup F) = 58

n(s) = n(S) - n(S \cap F) = 54 - n(S \cap F)

n(f) = n(F) - n(S \cap F) = 28 - n(S \cap F)

So

n(S \cup F) = n(s) + n(f) + n(S \cap F)

58 = 54 - n(S \cap F) + 28 - n(S \cap F) + n(S \cap F)

n(S \cap F) = 24

So the correct answer is:

b) 24

3 0
3 years ago
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