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Gekata [30.6K]
3 years ago
12

PLEASE HELP

Mathematics
1 answer:
swat323 years ago
8 0

Answer: C

Step-by-step explanation:

because they solution can only be use to one answer

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A company bought 28 desks for each<br> of its 17 offices. How many desks were<br> bought altogether?
nika2105 [10]

Answer:

476

Step-by-step explanation:

THAT SHOULD BE 28*17 Wich is 476

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Which number is greater?<br><br> A. 3.33 x 10^7<br> B. 2.34 x 10^5
Zina [86]

Answer:

3.33times 10^7 because when it is possible to substract 2.24times10^5 from it

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Which statement correctly describes order of operations (PEMDAS)?
Serjik [45]

Answer:

B

Step-by-step explanation:

parentheses exponents multiplication division addition subtraction

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Rewrite the expression 4+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B16-%284%29%285%29%7D" id="TexFormula1" title="\sqrt{16-(4)(
Inessa05 [86]

Answer:

2+i

Step-by-step explanation:

Given the expression:

\dfrac{4+\sqrt{16-(4)(5)}}{2}

To find:

The expression of above complex number in standard form a+bi.

Solution:

First of all, learn the concept of i (pronounced as <em>iota</em>) which is used to represent the complex numbers. Especially the imaginary part of the complex number is represented by i.

Value of i =\sqrt{-1}.

Now, let us consider the given expression:

\dfrac{4+\sqrt{16-(4)(5)}}{2}\\\Rightarrow \dfrac{4+\sqrt{16-(4\times 5)}}{2}\\\Rightarrow \dfrac{4+\sqrt{16-20}}{2}\\\Rightarrow \dfrac{4+\sqrt{-4}}{2}\\\Rightarrow \dfrac{4+\sqrt{(-1)(4)}}{2}\\\Rightarrow \dfrac{4+\sqrt{(-1)}\sqrt4}{2}\\\Rightarrow \dfrac{4+\sqrt4i}{2} \ \ \ \ \ (\because \sqrt{-1} =i) \\\Rightarrow \dfrac{4+2i}{2}\\\Rightarrow 2+i

So, the given expression in standard form is 2+i.

Let us compare with standard form a+bi so we get a =2, b =1.

\therefore The standard form of

\dfrac{4+\sqrt{16-(4)(5)}}{2}

is: \bold{2+i}

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2 years ago
What is the least common multiple of 3,7,9
KengaRu [80]


The least common multiple is 63.

Explanation: 63 is the least number that 3 7 and 9 can go into evenly. Therefore, it is the least common multiple.

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