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IRINA_888 [86]
2 years ago
7

Express 1/243 as a power

Mathematics
1 answer:
nikdorinn [45]2 years ago
5 0

Answer:

logbase3(1/243)

Step-by-step explanation:

This is the equation you would use to solve.

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Length=x<br>width=x+16<br>AREA of rectangle=80X^2<br>FIND x
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Here is same thing but different numbers

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Security fence encloses a rectangular area on one side of a park in a city. three sides of fencing are​ used, since the fourth s
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Let assume a the width and b the length of the rectangular area.
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6 0
3 years ago
Find the value of a square + b square when a+b = 8 and ab = 10
Ne4ueva [31]

As we know,

\boxed{ \boxed{(a + b) {}^{2}  =  {a}^{2}  +  {b}^{2}  + 2ab}}

now, let's plug the given values to find a² + b²

  • (8) {}^{2}  =  {a}^{2}  +  {b}^{2}  + (2 \times 10)

  • 64 =   {a}^{2}  +  {b}^{2}  + 20

  • {a}^{2} +   {b}^{2}  = 64 - 20

  • a {}^{2} +  b {}^{2}  = 44
5 0
3 years ago
What is the sum of 20x^2-10x-30
ivann1987 [24]

Answer:

The sum of the roots is 0.5

Step-by-step explanation:

<u><em>The correct question is</em></u>

What is the sum of the roots of 20x^2-10x-30

we know that

In a quadratic equation of the form

ax^{2} +bx+c=0

The sum of the roots is equal to

-\frac{b} {a}

in this problem we have

20x^{2} -10x-30=0  

so

a=20\\b=-10\\c=-30

substitute

-\frac{(-10)} {20}=0.5

<u><em>Verify</em></u>

Find the roots of the quadratic equation

The formula to solve a quadratic equation is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

a=20\\b=-10\\c=-30

substitute

x=\frac{-(-10)\pm\sqrt{-10^{2}-4(20)(-30)}} {2(20)}

x=\frac{10\pm\sqrt{2,500}} {40}

x=\frac{10\pm50} {40}

x=\frac{10+50} {40}=1.5

x=\frac{10-50} {40}=-1

The roots are x=-1 and x=1.5

The sum of the roots are

-1+1.5=0.5 ----> is ok

5 0
3 years ago
Solve for X when the surface area is 298ft^2
jok3333 [9.3K]

Step-by-step explanation:

Total surface area of cuboid= 2(lb+bh+hl)

= 298ft²=2(28+4x+7x)

= 149=28+11x

= 121=11x

= 11=x

6 0
2 years ago
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