Carleen has 104 pieces of candy leftover from Halloween. She would like to distribute them evenly to the 8 kids on her block. Wr
2 answers:
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Answer:
the dimension of the poster = 90 cm length and 60 cm width i.e 90 cm by 60 cm.
Step-by-step explanation:
From the given question.
Let p be the length of the of the printed material
Let q be the width of the of the printed material
Therefore pq = 2400 cm ²
q =
To find the dimensions of the poster; we have:
the length of the poster to be p+30 and the width to be
The area of the printed material can now be:
=
Let differentiate with respect to p; we have
Also;
For the smallest area
p² = 3600
p =√3600
p = 60
Since p = 60 ; replace p = 60 in the expression q = to solve for q;
q =
q =
q = 40
Thus; the printed material has the length of 60 cm and the width of 40cm
the length of the poster = p+30 = 60 +30 = 90 cm
the width of the poster = =
= 40 + 20 = 60
Hence; the dimension of the poster = 90 cm length and 60 cm width i.e 90 cm by 60 cm.
To solve this problem you must apply the proccedure shown below:
1. You have the following points given in the problem above:
A<span>(-2,3), B(9,3), C(5,6) and D(2,6)
2. When you plot them, you obtain the figure shown in the graph attached.
3. Therefore, as you can see, the answer is: the figure is a trapezoid, which is define as a quadrilateral with two parallel sides.</span>
1. You have the following points given in the problem above:
A<span>(-2,3), B(9,3), C(5,6) and D(2,6)
2. When you plot them, you obtain the figure shown in the graph attached.
3. Therefore, as you can see, the answer is: the figure is a trapezoid, which is define as a quadrilateral with two parallel sides.</span>
Answer:
A ≈ 65.8 m²
Step-by-step explanation:
Given 2 sides and the angle between them then the area (A) is
A = bc sinA
= 0.5 × 19.9 × 10.7 × sin38.17°
≈ 65.8 m² ( to 1 dec. place )