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maw [93]
3 years ago
10

Your welcome 95 points gg

Computers and Technology
2 answers:
dexar [7]3 years ago
6 0
Thank you so much c:
STatiana [176]3 years ago
4 0

Answer:

tysm :))

Explanation:

have a great day

You might be interested in
Purpose of this project is to increase your understanding of data, address, memory contents, and strings. You will be expected t
STALIN [3.7K]

Answer:

See explaination for the details

Explanation:

#Starting point for code/programm

main:

la $a0,newLine #Print a new line

li $v0,4

syscall

# Find the number of occurence of a string in the given sentence

la $a0,prompt1 # Prompt the user to enter the first string.

li $v0,4

syscall

li $v0, 8 # Service 8 = read input string

la $a0, fword

li $a1, 9

syscall

la $a0,prompt2 # Prompt the user to enter the second string.

li $v0,4

syscall

li $v0, 8 # Service 8 = read input string

la $a0, sword

li $a1, 9

syscall

# process first word

li $t4,0 # Intialize the couter to 0

la $t0,sstatement # Store the statement into $t0

nstart1: la $t1,fword # Store the search word into $t1

loop1: # loop1 finds the number of occurences

# of input word in the given statment

lb $t2,($t0) # Load the starting address(character) of

# sstatement into $t2

lb $t3,($t1) # Load the starting address of input word

# into $t3

beq $t3,'\n',inc_counter1

beqz $t3,inc_counter1 # If $t3 is null , exit loop and print output

beqz $t2,print_output1 # If $t2 is null , exit loop and print output

move $a0,$t2 # Convert $t2 to lower, if it is upper case

jal convert2lower

move $t2,$v0 # Store the return($v0) value into $t2

move $a0,$t3 # Convert $t3 to lower, if it is upper case

jal convert2lower

move $t3,$v0 # Store the return($v0) value into $t3

bne $t2,$t3,next_char1 # If both characters are not matched current

# character in the string, go to next character

addiu $t0,$t0,1 # otherwise, increment both indexes

addiu $t1,$t1,1

j loop1 # go to starting of the loop

next_char1:

la $t5,fword

bne $t5,$t1,nstart1

la $t1,fword # Store the input word into $t1

addiu $t0,$t0,1 # Increment the index to goto next character

j loop1 # go to starting of the loop

inc_counter1:

addi $t4,$t4,1 # Increment the frequency counter by 1

la $t1,fword # Store input word into $t1

j loop1 # go to starting of the loop

print_output1:

la $t0,fword

L1:

lb $a0,($t0)

beq $a0,'\n',exL1

jal convert2upper

move $a0,$v0

li $v0,11

syscall

addiu $t0,$t0,1

j L1

exL1:

la $a0,colon

li $v0,4

syscall

la $a0, dash

li $v0, 4

syscall

move $a0,$t4

li $v0,1

syscall # print new line

la $a0,newLine

li $v0,4

syscall

# process second word

li $t4,0 # Intialize the couter to 0

la $t0,sstatement # Store the statement into $t0

nstart2: la $t1,sword # Store the search word into $t1

loop2: # loop1 finds the number of occurences

# of input word in the given statment

lb $t2,($t0) # Load the starting address(character) of

# sstatement into $t2

lb $t3,($t1) # Load the starting address of input word

# into $t3

beq $t3,'\n',inc_counter2

beqz $t3,inc_counter2 # If $t3 is null , exit loop and print output

beqz $t2,print_output2 # If $t2 is null , exit loop and print output

move $a0,$t2 # Convert $t2 to lower, if it is upper case

jal convert2lower

move $t2,$v0 # Store the return($v0) value into $t2

move $a0,$t3 # Convert $t3 to lower, if it is upper case

jal convert2lower

move $t3,$v0 # Store the return($v0) value into $t3

bne $t2,$t3,next_char2 # If both characters are not matched current

# character in the string, go to next character

addiu $t0,$t0,1 # otherwise, increment both indexes

addiu $t1,$t1,1

j loop2 # go to starting of the loop

next_char2:

la $t5,sword

bne $t5,$t1,nstart2

la $t1,sword # Store the input word into $t1

addiu $t0,$t0,1 # Increment the index to goto next character

j loop2 # go to starting of the loop

inc_counter2:

addi $t4,$t4,1 # Increment the frequency counter by 1

la $t1,sword # Store input word into $t1

j loop2 # go to starting of the loop

print_output2:

la $t0,sword

L2:

lb $a0,($t0)

beq $a0,'\n',exL2

jal convert2upper

move $a0,$v0

li $v0,11

syscall

addiu $t0,$t0,1

j L2

exL2:

la $a0,colon

li $v0,4

syscall

la $a0, dash2

li $v0, 4

syscall

move $a0,$t4

li $v0,1

syscall

exit:

# Otherwise, end the program

li $v0, 10 # Service 10 = exit or end program

syscall

############################ subroutine - convert2lower #################################

convert2lower: # Converts a character(stored in $a0) to

# its lower case, if it is upper case

# and store the result(lower case) in $v0

move $v0,$a0

blt $a0,'A',return

bgt $a0,'Z',return

subi $v0,$a0,-32

return: jr $ra # Return the converted(lower case) character

############################## subroutine - convert2upper ##################################

convert2upper: # Converts a character(stored in $a0) to

# its upper case, if it is lower case

# and store the result(upper case) in $v0

move $v0,$a0

blt $a0,'a',return2

bgt $a0,'z',return2

addiu $v0,$a0,-32

return2: jr $ra # Return the converted(lower case) character

4 0
3 years ago
Select the correct text in the passage. Idenufy the phrase that shows the use of a non-contact-type temperature sensor. Jim work
suter [353]

Answer:

where he is allowed only to enter on successful biometric verification by sensor at the gate,,it shows to some extent there is no contact,,,the molten we are told is risky so there should be no close contact with it,,

5 0
3 years ago
What is the difference between a doubly linked list and a singly linked list?
lina2011 [118]

Answer:

A doubly linked list links each element to both its predecessor and successor, whereas a singly linked list only points to its successor.

Explanation:

Doubly linked lists are easier to iterate backwards. With singly linked lists you'd have to start at the beginning every time.

7 0
4 years ago
Two strings are anagrams if they are written using the same exact letters. Write a method to check if given two strings are anag
Andre45 [30]

Answer:

Check the explanation

Explanation:

import java.util.Scanner;

public class Anagrams {

   public static int count(String s, char ch) {

       int c = 0;

       for (int i = 0; i < s.length(); ++i) {

           if (s.charAt(i) == ch) {

               c++;

           }

       }

       return c;

   }

   public static boolean isAnagram(String s1, String s2) {

       char ch;

       s1 = s1.toLowerCase();

       s2 = s2.toLowerCase();

       for (int i = 0; i < s1.length(); ++i) {

           ch = s1.charAt(i);

           if (ch != ' ' && count(s1, ch) != count(s2, ch)) {

               return false;

           }

       }

       for (int i = 0; i < s2.length(); ++i) {

           ch = s2.charAt(i);

           if (ch != ' ' && count(s1, ch) != count(s2, ch)){

               return false;

           }

       }

       return true;

   }

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.print("Enter the first string: ");

       String s1 = in.nextLine();

       System.out.print("Enter the second string: ");

       String s2 = in.nextLine();

       if (isAnagram(s1, s2)) {

           System.out.println(s1 + " and " + s2 + " are anagrams");

       } else {

           System.out.println(s1 + " and " + s2 + " are NOT anagrams");

       }

   }

}

Kindly check the output image below.

4 0
4 years ago
Read 2 more answers
Question 1
Leto [7]

Answer:

The answer is "4bout T!me" and "word"

Explanation:

In the given java program code, the two choices that are "4bout T!me" and "word" were correct, because it uses the double quote, and its example can be defined as follows:

Example:

public class Exa //defining class Exa

{

public static void main(String[] args) //defining main method

{

    String x ="4bout T!me";//defining String variable x and assign value

       String y ="word";//defining String variable y and assign value

 System.out.println(x+"  "+y);//print message

}

}

Output:

4bout T!me  word

8 0
3 years ago
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