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Zarrin [17]
3 years ago
14

Suppose you select a ball by first picking one of two boxes at random and then selecting a ball from this box. The first box con

tains two white balls and three blue balls and the second box contains four white balls and one blue ball. What is the probability that you picked a ball from the first box if you have drawn a blue ball
Mathematics
1 answer:
Alexxx [7]3 years ago
3 0

Answer:

Probability of selecting a ball from the first ball if it is a blue ball =  = 0.75

Step-by-step explanation:

Number of blue balls in the first box = 3

Number of blue balls in the second box = 1

Total number of blue balls = 3 + 1

Total number of blue balls = 4

Probability = (Number of possible outcomes)/(Number of total outcomes)

Probability of selecting a ball from the first ball if it is a blue ball = 3/4

Probability of selecting a ball from the first ball if it is a blue ball =  = 0.75

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A theme park had 1099 visitors in 3 days.There were twice as many visitors on saturday than on Friday.There were 234 more visito
Blababa [14]

Answer: there were 692 visitors on Saturday.

Step-by-step explanation:

Let x represent the number of visitors that were there on Friday.

Let y represent the number of visitors that were there on Saturday.

Let z represent the number of visitors that were there on Sunday.

The theme park had 1099 visitors in 3 days. It means that

x + y + z = 1099- - - - - - - - - - - - - -1

There were twice as many visitors on saturday than on Friday. This means that

y = 2x

x = y/2

There were 234 more visitors on Sunday than on Saturday. This means that

z = y + 234

Substituting x = y/2 and z = y + 234 into equation 1, it becomes

y/2 + y + y + 234 = 1099

Cross multiplying by 2, it becomes

y + 2y + 2y + 468 = 2198

5y = 2198 - 468

5y = 1730

x = 1730/5

x = 346

y = 2x = 2 × 346

y = 692

z = y + 234 = 692 + 234

z = 926

3 0
3 years ago
Help please!!!!!!!!!
In-s [12.5K]

ANSWER

24


EXPLANATION

For a matrix A of order n×n, the cofactor C_{ij} of element a_{ij} is defined to be


   C_{ij} = (-1)^{i+j} M_{ij}


M_{ij} is the minor of element a_{ij} equal to the determinant of the matrix we get by taking matrix A and deleting row i and column j.


Here, we have


   C_{11} = (-1)^{1+1} M_{11} = M_{11}


M₁₁ is the determinant of the matrix that is matrix A with row 1 and column 1 removed. The bold entries are the row and the column we delete.


   \begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right)  \end{aligned}


Since the determinant of a 2×2 matrix is


   \det\left(  \begin{bmatrix} a & b \\ c& d  \end{bmatrix} \right) = ad-bc


it follows that


   \begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right) \\ &= (0)(-8) - (-3)(8) \\ &= -(-24) \\ &= 24 \end{aligned}


so C_{11} = M_{11} = 24

4 0
3 years ago
Find the next three sequence of 1,3, 9, 27,<br>​
Andreyy89

Answer: 81, 243, 729

Step-by-step explanation:

<u>STEP ONE: Find a pattern in the sequence</u>

3 ÷ 1 = 3

9 ÷ 3 = 3

27 ÷ 9 = 3

As we can see from the given sequence, each number multiplies 3 to get the next term.

<u>STEP TWO: Find the next three terms</u>

27 × 3 = 81

81 × 3 = 243

243 × 3 = 729

Hope this helps!! :)

Please let me know if you have any questions

4 0
3 years ago
Select all the equations that match the tape diagram
Ksivusya [100]

Answer:

x=4.5

A, B, D, and F

7 0
3 years ago
A wise investor purchased a plot of land in 1947 for $84000
jarptica [38.1K]
The answer will be $82063
7 0
3 years ago
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