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3 years ago

Solve for x : 4/5 x − 2 = 7

Mathematics

2 answers:

Sunny_sXe [5.5K]3 years ago

8 0

Answer: x = 45/4

Step-by-step explanation:

PtichkaEL [24]3 years ago

8 0

Answer:

11 1/4 simplified form

45/4 exact form

11.25 decimal form

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Answer:

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2 years ago

Read 2 more answers

2/5x+y=3<br> solve the equation for y.

stira [4]

2/5x+y=3

-2/5x -2/5x

y=-2/5x+3

Does y = to whole number or just like that? if it Whole number I will solve it tell me

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3 years ago

by selling an item at $20.70, a trader makes a profit of 15%. at what price should he sell the item so as to make a profit of 35

Alisiya [41]

Answer:

24.3 i think

Step-by-step explanation:

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3 years ago

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5x^(-2)-17x^(-1)+6<br> i’m so confused pls help<br> will give brainliest

laila [671]

It's a quadratic equation in disguise. If you let $y=x^{-1}$ , then $y^2=x^{-2}$ , and we can rewrite the equation as

$5y^2-17y+6=0$

Solve for $y$ however you like; we get $y=\dfrac25$ and $y=3$ .

But we want to solve for $x$ , so we have

$y=x^{-1}=\dfrac25\implies x=\dfrac52$

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3 years ago

On February 1, the electricity meter reading for the Smith residence was 19,423 kilowatt hours. On March 1, the meter read 20,28

Karolina [17]

A. How many kilowatt hours of electricity did the Smiths use during February?

Kilowatt hours of electricity the Smiths used during February:
Meter read on March 1 - meter read on February 1 =
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Answer: The Smiths used 865 kilowatt hours of electricity during February

b. How many kilowatt hours did they use during March?

Kilowatt hours of electricity the Smiths used during March:
Meter read on April 1 - meter read on March 1 =
21,163 kilowatt hours - 20,288 kilowatt hours =
875 kilowatt hours
Answer: The Smiths used 875 kilowatt hours of electricity during March

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4 years ago