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3 years ago

9

What is six-sevents divided by four? Please answer using fractions! Will give brianliest

1 answer:

galina1969 [7]3 years ago

8 0

Answer:

107/500

Step-by-step explanation:

You might be interested in

What are the roots of 3x2 + 10 = 4x?

sveticcg [70]

Answer:

Option C is correct.

roots of the given equation , $x =\frac{2\pm i\sqrt{26}}{3}$

Step-by-step explanation:

Given the equation: $3x^2+10 = 4x$

We can write this equation as:

$3x^2-4x + 10 =0$

A quadratic equation is in the form of $ax^2+bx+c =0$ ......[1] where a,b ,c are the coefficient and x is the variable,

the solution of the equation is given by;

$x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

On comparing given equation with equation [1] we get;

a = 3 , b = -4 and c =10

So, the solution of the given equation is given by;

$x = \frac{-(-4)\pm\sqrt{(-4)^2-4(3)(10)}}{2(3)}$

or

$x = \frac{4\pm\sqrt{(16-120}}{6} = \frac{4\pm\sqrt{(-104)}}{6} = \frac{4\pm\sqrt{(-4 \times 26)}}{6}$

or

$x =\frac{4\pm2 \sqrt{(-26)}}{6} = \frac{4\pm2 i\sqrt{26}}{6}$ [∴ $\sqrt{-1} = i$

Simplify:

$x =\frac{2\pm i\sqrt{26}}{3}$

therefore, the roots of the given equation are; $x =\frac{2\pm i\sqrt{26}}{3}$

5 0

3 years ago

Read 2 more answers

1. Which is greater than 4?<br><br> (a) 5,<br><br> (b) -5,<br><br> (c) -1/2,<br><br> (d) -25.

Gala2k [10]

Answer:

(a) 5

5 is greater than 4

5 0

3 years ago

Read 2 more answers

The number of customers that visit a local small business is 46,900 and has been continuously declining at a rate of 3.2% each y

anygoal [31]

V=Vo (1-r/100)^n
V=46900(1-3.2/100)^8
V=46900(96.8/100)^8
V=46900*(.968)^8
V=36155.61
V=36155(approx)

4 0

3 years ago

Carl likes to work out 20 minutes a day. Today, he was only able to exercise 0.8 of his usual time. How many minutes did Carl wo

goldenfox [79]

answer: 16 minutes

Step-by-step explanation:

0.8 would mean 80% of 20minutes.

80/100 × 20 =

=1600/100

=16 minutes

7 0

3 years ago

Prove that: (secA-cosec A) (1+cot A +tan A) =( sec^2A/cosecA)-(Cosec^2A/secA)<br>

Ksju [112]

Step-by-step explanation:

$(\sec A - \csc A)(1 + \cot A + \tan A)$

$=(\sec A - \csc A)\left(1 + \dfrac{\cos A}{\sin A} + \dfrac{\sin A}{\cos A} \right)$

$=(\sec A - \csc A)\left(1 + \dfrac{\cos^2 A + \sin^2 A}{\sin A\cos A} \right)$

$=(\sec A - \csc A)\left(\dfrac{1 + \sin A \cos A}{\sin A \cos A} \right)$

$=\left(\dfrac{\frac{1}{\cos A} - \frac{1}{\sin A}+\sin A - \cos A}{\sin A\cos A}\right)$

$=\dfrac{\sin A - \sin A \cos^2A - \cos A + \cos A\sin^2A}{(\sin A\cos A)^2}$

$=\dfrac{\sin A(1 - \cos^2A) - \cos A (1 - \sin^2 A)}{(\sin A\cos A)^2}$

$=\dfrac{\sin^3A - \cos^3A}{\sin^2A\cos^2A}$

$=\dfrac{\sin A}{\cos^2A} - \dfrac{\cos A}{\sin^2A}$

$=\left(\dfrac{1}{\cos A}\right)\left(\dfrac{\sin A}{1}\right) - \left(\dfrac{1}{\sin^2A}\right) \left(\dfrac{\cos A}{1}\right)$

$=\sec^2A\csc A - \csc^2A\sec A$

5 0

3 years ago