Answer:
3977g
Step-by-step explanation:
We are told that these two shapes are similar and we were given the following values form the question
Surface area of a is 28cm²
Surface area of b is 40.32cm²
Mass of b is 6912g
Step 1
The first step is to find the relationship between the surface area of b and a and to do this we introduce a constant k
It is important to note that because we are dealing with surface area , the constant k will be squared.
Therefore the relationship between the surface area of b and a
Surface area of b = k² × surface area of a
40.32cm² = k² × 28cm²
Divide both sides by 28cm²
k²= 40.32cm²/28cm²
k²= 1.44cm²
The next step is to find the square root of both sides
√k² = √1.44cm²
k = 1.2cm
Step 2
We have to find the relationship between the masses of the similar objects. We would also introduce a constant 'k' and because we are have to find the mass of object a , k will be cubed
The relationship between mass b and a is given as follows:
Mass of b= k³× mass of a
Mass of b = 6912g
k = 1.2cm
Therefore,
6912g = (1.2cm)³ × mass of a
6912g = 1.738cm³× mass of a
Mass of a = 6912g/1.738cm³
Mass of a = 3976.985g
Approximately the Mass of a to the nearest whole number = 3977g