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lorasvet [3.4K]
3 years ago
15

Help asap pls for brainliest!

Mathematics
2 answers:
Brut [27]3 years ago
8 0

Answer:

D

Step-by-step explanation:

Anvisha [2.4K]3 years ago
4 0

Answer:

D

Bro this is the answer!

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Will give brainliest!
goblinko [34]
As the weight increases, the price increases.
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3 years ago
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One side of trapezoid is 10 inches. The side parrellel to this is twice as long as this side. The height is half as long as the
madam [21]
The first side is 10 inches
the side parallel to this is (10×2)= 20 inches
Height is half the length=1/2×20=10 inches
The area of trapezium is given by:
Area=1/2×h×(a+b)
where a and b are the sides, h is the height. Thus the area will be:
Area=1/2×10×(20+10)
=1/2×10×30
=150 sq. inches
7 0
3 years ago
What is the distance between the points (5, 6) and (5, 2)? a. 1 b. 3 c. 4 d. 8
postnew [5]
The\ distance\ between\ A(x_A;\ y_A)\ and\ B(x_B;\ y_B):\\\\d=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}

(5;\ 6);\ (5;\ 2),\ subtitute\\\\d=\sqrt{(2-6)^2+(5-5)^2}=\sqrt{(-4)^2+0^2}=\sqrt{16}=4
4 0
3 years ago
Find the value of x. x√5=x^4​
Kaylis [27]

Answer:

x=0,\sqrt[6]{5}

Decimal form,

x=0,1.30766048......

Step-by-step explanation:

x\sqrt{5}=x^{4}

x\sqrt{5}-x^{4}=0

(take x as a common factor)

x(\sqrt{5}-x^{3})=0

So,

x=0 and \sqrt{5}-x^{3}=0

for \sqrt{5-x^{3}=0

(add x^{3} for both sides)

\sqrt{5}=x^{3}

x=\sqrt[3]{\sqrt[2]{5} } (multiply 3 by 2)

x=\sqrt[6]{5}

So,

x=0,\sqrt[6]{5}

5 0
3 years ago
What is the scale factor from figure A to figure B?
Andrej [43]

Answer:

hi its simple.

Step-by-step explanation:

9;3

or simplified...

3;1

3 0
3 years ago
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