about 5 watts (5W) of power
<u>Answer</u>
3.4 s
<u>Explanation</u>
The question can be solve by using the 2nd Newton's law of motion.
s = ut + 1/2at²
Before she is pushed, the initial velocity is zero.
u = 0
Now the equation becomes
s = 0 + 1/2at²
s = 1/2at²
25 = 1/2 × 4.3 × t²
50 = 4.3t²
t² = 50/4.3
= 11.628
t = √11.628
= 3.4 s
Answer:
Explanation:
Light year is the distance , ray of light travels in one year at the speed of 186000 mi/s
Distance traveled by light in one year
= speed x time
186000 x 365 x 24 x 60 x 60 miles
= 5.8657 x 10¹² mi
the Earth – Sun distance in light- years.
= 92.9 × 10⁶ mi. / 5.8657 x 10¹² mi light years
= 15.84 x 10⁻⁶ light years
To calculate in terms of parsec
1 degree angle
= 60 x 60 second
π /180 radian = 60 x 60 second
1 second = 3.14 / 180 x 3600
= 4.84 x 10⁻⁶ rad
one parsec = 1AU / one second
92.9 × 10⁶ mi / one second
= 92.9 × 10⁶ mi / 4.84 x 10⁻⁶ rad
= 19.19 x 10¹² mi
the Earth – Sun distance in parsec.
= 92.9 × 10⁶ mi. / 19.19 x 10¹² parsec.
= 4.84 x 10⁻⁶ parsec.
