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lana66690 [7]
3 years ago
6

Consider the graph showing two functions.

Mathematics
2 answers:
Fantom [35]3 years ago
7 0

Answer:

b

Step-by-step explanation:

BaLLatris [955]3 years ago
4 0

Answer:

1st anwser

Step-by-step explanation:

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an algebra teacher drove by a farmyard full of chickens and pigs.the teacher happened to notice that there were a totals of 100
LiRa [457]
I'll be honest, this is a pretty interesting question. I've never seen anything like it before!

We can start off by making equations with the given. If there are 100 heads, that means that the total number of chickens and pigs combined is 100. Thus, we can form our first equation:

p + c = 100
('p' represents number of pigs, and 'c' represents number of chickens)

We also know that there are 270 legs total. Since chickens have 2 and pigs have 4, we can make the following equation:
2c + 4p = 270

I suppose the quickest way to solve for this equation is to use the subtraction method. Put the equations on top of each other:

2c + 4p = 270
c + p = 100
___________
Multiply the bottom equation by -2;

2c + 4p = 270
-2c -2p = 100
____________
"Add" these two equations together:

2c + 4p = 270
-2c -2p = -200
___________
2p = 70

Divide both sides by 2:
p = 35

Ah, finally. Now that we know that there are 35 pigs, input this variable into the first equation to find the number of chickens:

c + 35 = 100
Subtract:
c = 65

There are 35 pigs and 65 chickens
-T.B.
3 0
3 years ago
16. Is 4/9 a terminating or repeating decimal?<br> Terminating Decimal<br> Repeating Decimal
Sonbull [250]
Repeating decimal is the answer
5 0
3 years ago
What time what equals -30 and adds to +10
Hoochie [10]
I think its -40 because it looks like you have negative 40 then ur adding 10 
5 0
3 years ago
What is the value of the expression 24/x when x = 8?
erma4kov [3.2K]

Answer:

Itd be 3 becaus 24/8 is 3

8 0
3 years ago
The sum of the diagonals of a rhombus is 5√2.
Alex
Greetings!
Let ABCD be a rhombus
AC + BD = 5√2 cm

Area of ABCD = Ar△ABD + Ar △BCD
= \frac{1}{2} \times BD \times AO + \frac{1}{2} \times BD \times OC
= \frac{1}{2} BD (AO + OC)
\frac{1}{2} BD \times AC

So, \frac{ BD \times AC}{2} = 4 \: cm {}^{2}
BD \times AC = 8
Now, AC + \: BD = 5 \sqrt{2}

Squaring both sides, we get
AC {}^{2} + BD {}^{2} + 2 AC.BD =50
AC {}^{2} + BD {}^{2} + 2 \times 8 = 50
AC {}^{2} + BD {}^{2} = 50 - 16
AC {}^{2} + BD {}^{2} = 34

In △AOB, we have
OA {}^{2} + OB {}^{2} =AB {}^{2}
( \frac{ AC }{2} ) {}^{2} + ( \frac{ BD}{2} ) {}^{2} = AB {}^{2}
\frac{ AC {}^{2} } {4} + \frac{ BD {}^{2} }{4} = AB {}^{2}
AC {}^{2} + BD {}^{2} = 4 AB {}^{2}
34 = 4 AB {}^{2}

Square rooting both sides
\sqrt{34} = 2 AB
Perimeter = 4 \: AB \\ = 2 \times 2 \: AB \\ = 2 \: \times \sqrt{34 } \\ = 2 \sqrt{34 \: } units.

Hope it helps!

7 0
3 years ago
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