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Anarel [89]
10 months ago
9

Model Real Life You and a partner

Mathematics
1 answer:
shutvik [7]10 months ago
7 0

No. Using multiplication and division, you and your partner will not each get the same number of flips because one can flip 23 times, while the other does it 22 times.

<h3>What are mathematical operations?</h3>

The basic mathematical operations include addition, subtraction, multiplication, and division.

These mathematical operations are performed on numbers, variables, equations, and functions to determine numerical results.

In this situation, we first multiply to get the total number of times the 3 bottles can be flipped.

This total is divided by 2 to see if there will not be a remainder.  The result of the division operation is an odd value.

The number of bottles for flipping = 3

The number of times to flip each bottle = 15 times

The total number of times to flip the 3 bottles = 45 times 93 x 15)

The number of those conducting the bottle flipping experiment = 2

The number of times each partner can flip the bottles evenly = 22.5 times (45/2)

Each partner cannot flip the same number of times based on the mathematical operations because 45 is not an even number.

Learn more about mathematical operations at brainly.com/question/20628271

#SPJ1

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Goryan [66]
Data: (Cylinder)
h (height) = 8 cm
r (radius) = 5 cm
Adopting: \pi \approx 3.14
V (volume) = ?

Solving:(<span>Cylinder volume)
</span>V = h* \pi *r^2
V = 8*3.14*5^2
V = 8*3.14*25
\boxed{ V_{cylinder}  = 628\:cm^3}

<span>Note: Now, let's find the volume of a hemisphere.
</span>
Data: (hemisphere volume)
V (volume) = ?
r (radius) = 5 cm
Adopting: \pi \approx 3.14

If: We know that the volume of a sphere is V = 4 * \pi *  \frac{r^3}{3}, but we have a hemisphere, so the formula will be half the volume of the hemisphere V =  \frac{1}{2}  * 4 * \pi *  \frac{r^3}{3} &#10;

Formula: (<span>Volume of the hemisphere)
</span>V = \frac{1}{2} * 4 * \pi * \frac{r^3}{3}

Solving:
V = \frac{1}{2} * 4 * \pi * \frac{r^3}{3}
V = \frac{1}{2} * 4 * 3.14 * \frac{5^3}{3}
V = \frac{1}{2} * 4 * 3.14 * \frac{125}{3}
V =  \frac{1570}{6}
\boxed{V_{hemisphere}\approx 261.6\:cm^3}


<span>Now, to find the total volume of the figure, add the values: (cylinder volume + hemisphere volume)
</span>
Volume of the figure = cylinder volume + hemisphere volume
Volume of the figure = 628 cm³ + 261.6 cm³
\boxed{\boxed{Volume\:of\:the\:figure = 1517.6\:cm^3}}\end{array}}\qquad\quad\checkmark
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Answer:

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Thus, we have this as;

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